This is the code:
这是代码:
unsigned int number;
FILE* urandom = fopen("/dev/urandom", "r");
if (urandom) {
size_t bytes_read = fread(&number, 1, sizeof(number), urandom);
DCHECK(bytes_read == sizeof(number));
fclose(urandom);
} else {
NOTREACHED();
}
If not, how do I make it thread-safe?
如果没有,我如何使其线程安全?
1 个解决方案
#1
10
As long as each execution of the function is in its own thread (i.e., the local variables number
, urandom
, bytes_read
are not shared between threads), I don't see any thread-safety problems. Each thread will then have its own file descriptor into /dev/urandom
. /dev/urandom
can be opened simultaneously from multiple processes, so that's okay.
只要函数的每次执行都在自己的线程中(即,局部变量号,urandom,bytes_read不在线程之间共享),我就看不到任何线程安全问题。然后每个线程都有自己的文件描述符到/ dev / urandom。 / dev / urandom可以从多个进程同时打开,所以没关系。
By the way, /dev/urandom
can fail to open, and your code should deal with it. Some causes are: running out of available file descriptors; /dev
not properly mounted (although in this case you have bigger problems); your program is being run in a special chroot
which denies access to any devices; etc.
顺便说一下,/ dev / urandom可能无法打开,你的代码应该处理它。一些原因是:用完了可用的文件描述符; / dev没有正确安装(虽然在这种情况下你有更大的问题);你的程序是在一个特殊的chroot中运行的,它拒绝访问任何设备;等等
#1
10
As long as each execution of the function is in its own thread (i.e., the local variables number
, urandom
, bytes_read
are not shared between threads), I don't see any thread-safety problems. Each thread will then have its own file descriptor into /dev/urandom
. /dev/urandom
can be opened simultaneously from multiple processes, so that's okay.
只要函数的每次执行都在自己的线程中(即,局部变量号,urandom,bytes_read不在线程之间共享),我就看不到任何线程安全问题。然后每个线程都有自己的文件描述符到/ dev / urandom。 / dev / urandom可以从多个进程同时打开,所以没关系。
By the way, /dev/urandom
can fail to open, and your code should deal with it. Some causes are: running out of available file descriptors; /dev
not properly mounted (although in this case you have bigger problems); your program is being run in a special chroot
which denies access to any devices; etc.
顺便说一下,/ dev / urandom可能无法打开,你的代码应该处理它。一些原因是:用完了可用的文件描述符; / dev没有正确安装(虽然在这种情况下你有更大的问题);你的程序是在一个特殊的chroot中运行的,它拒绝访问任何设备;等等