如何让程序重启？ （Linux进程）

I'm trying to get my program to restart itself, but nothing seems to work. I tried using fork(), but after killing the parent process the child gets killed too.

我正试图让我的程序重新启动，但似乎没有任何工作。我尝试使用fork（），但在杀死父进程后，孩子也被杀死了。

CODE

码

void sigup_handler(int signum) {
    int pid = fork();
    if (pid == 0) {
        execve("prog2", NULL); 
    }
    else
        kill(getpid(), SIGTERM);
}

int main() {
    puts("Program 2 started.");
    signal(SIGHUP, sigup_handler);
    sleep(50); 
    puts("Program 2 terminated.");
    return 0;
}

3 个解决方案

#1

Why bother with the fork if you're just going to kill the parent? Just do the exec. The new instance of the program will still be the same process but will effectively be rebooted.

如果你要杀死父母，为什么还要用叉子呢？做执行官。该程序的新实例仍将是相同的过程，但将有效地重新启动。

#2

Use 2 levels of forking. A parent "monitor" app which forks off children and monitors their status. If a child dies, the monitor starts up a new one. The children then do their own forking to do whatever it is they have to do.

使用2级分叉。一个父“监视器”应用程序，它会分叉儿童并监控他们的状态。如果孩子死了，监视器会启动一个新的。然后孩子们自己做分叉，做他们必须做的事情。

However, if you don't need the 'new' copy of the app to have the same state as the one that's being killed, then using exec() to start a fresh independent copy is likely a better option, saving you having to have that monitor copy sitting around.

但是，如果您不需要应用程序的“新”副本与被杀死的副本具有相同的状态，那么使用exec（）启动新的独立副本可能是更好的选择，从而节省您必须拥有的坐在那里的监控副本。

#3

You could use daemon(3) followed by execve(2)

您可以使用守护进程（3），然后使用execve（2）