I am trying to sort an array of objects by field, but I keep getting this error saying that "price / location cannot be resolved or is not a field", even though they both are fields, declared in the class Realestate. I got the same error about "not being a field" when I was dealing with ArrayList as well, so I moved to simple arrays of objects and I'm still getting the same error. What am I doing wrong? I found info about comparing arrays with Comparable and Comparator but I don't undertand how to apply whatever results to the sorting routine. Please HELP! These are my files:
我试图按字段对对象数组进行排序,但我不断收到此错误,说“价格/位置无法解析或不是字段”,即使它们都是字段,在类Realestate中声明。当我处理ArrayList时,我得到了关于“不是一个字段”的相同错误,所以我转移到简单的对象数组,我仍然得到相同的错误。我究竟做错了什么?我找到了有关将数组与Comparable和Comparator进行比较的信息,但我没有说明如何将任何结果应用于排序例程。请帮忙!这些是我的文件:
File Realestate:
public class Realestate {
static String location = "";
static String description = "";
static String price = "";
// constructor
public Realestate(String loc, String desc, String prc) {
location = loc;
description = desc;
price = prc;
}
}
File RealestateFinder:
import java.util.*;
public class RealestateFinder {
// Hold properties' info
static String[] locations = {"Miami", "Las Vegas", "Paris", "London"};
static String[] descriptions = {"1-bedroom", "2-bedrooms", "3-bedrooms", "penthouse"};
static String[] prices = {"1,000,000", "2,000,000", "3,000,000", "4,000,000"};
// Sort per field
public static void sortArray(Realestate arr[]) {
for(int x = 0; x < arr.length; ++x) {
//use array Sort
Arrays.sort(arr);
}
}
public static void main(String[] args) {
int numProperties = 4;
//Create new Realestate object newProperty
Realestate[] newProperty = new Realestate[numProperties];
// Initialize array of objects Realestate[] newProperty using arrays from top
for(int x = 0; x < newProperty.length; ++x) {
newProperty[x] = new Realestate(locations[x], descriptions[x], prices[x]); // constructor
}
//Get user's input
//...
while(true) {
if(holdUserInput == 1) {
//sort per price
sortArray(newProperty.price);//price cannot be resolved or is not a field
break;
}
else if(holdUserInput == 2) {
// sort per location
sortArray(newProperty.location);//location cannot be resolved or is not a field
break;
}
else {
System.out.println("Program Ended \n");
break;
}// end else statement
}// end while loop
}// end main()
}// end class RealestateFinder
1 个解决方案
#1
2
First you may not use static for your 3 fields, static
means that it's not relative to a particular instance, which i not what you want to
首先,你可能不会为你的3个字段使用静态,静态意味着它不是与特定实例相关,我不是你想要的
Then use a List
is easier to sort so :
然后使用List更容易排序,所以:
int numProperties = 4;
List<Realestate> list = new ArrayList<>();
for (int x = 0; x < numProperties; ++x) {
list.add(new Realestate(locations[x], descriptions[x], prices[x]));
}
Then, use existing methods to sort is quicker and easier to use :
然后,使用现有方法进行排序更快更容易使用:
while (true) {
if (holdUserInput == 1) {
list.sort(Comparator.comparing(Realestate::getPrice));
break;
} else if (holdUserInput == 2) {
list.sort(Comparator.comparing(Realestate::getLocation));
break;
} else if (holdUserInput == 2) {
list.sort(Comparator.comparing(Realestate::getDescription));
break;
} else {
System.out.println("Program Ended \n");
break;
}// end else statement
}
And finally, because there is not sense to use while(true)
and break
, better use switch
which is better :
最后,因为没有意义使用while(true)和break,所以最好使用更好的switch:
switch (holdUserInput) {
case 1:
list.sort(Comparator.comparing(Realestate::getPrice));
break;
case 2:
list.sort(Comparator.comparing(Realestate::getLocation));
break;
case 3:
list.sort(Comparator.comparing(Realestate::getDescription));
break;
default:
System.out.println("Program Ended \n");
break;
}
#1
2
First you may not use static for your 3 fields, static
means that it's not relative to a particular instance, which i not what you want to
首先,你可能不会为你的3个字段使用静态,静态意味着它不是与特定实例相关,我不是你想要的
Then use a List
is easier to sort so :
然后使用List更容易排序,所以:
int numProperties = 4;
List<Realestate> list = new ArrayList<>();
for (int x = 0; x < numProperties; ++x) {
list.add(new Realestate(locations[x], descriptions[x], prices[x]));
}
Then, use existing methods to sort is quicker and easier to use :
然后,使用现有方法进行排序更快更容易使用:
while (true) {
if (holdUserInput == 1) {
list.sort(Comparator.comparing(Realestate::getPrice));
break;
} else if (holdUserInput == 2) {
list.sort(Comparator.comparing(Realestate::getLocation));
break;
} else if (holdUserInput == 2) {
list.sort(Comparator.comparing(Realestate::getDescription));
break;
} else {
System.out.println("Program Ended \n");
break;
}// end else statement
}
And finally, because there is not sense to use while(true)
and break
, better use switch
which is better :
最后,因为没有意义使用while(true)和break,所以最好使用更好的switch:
switch (holdUserInput) {
case 1:
list.sort(Comparator.comparing(Realestate::getPrice));
break;
case 2:
list.sort(Comparator.comparing(Realestate::getLocation));
break;
case 3:
list.sort(Comparator.comparing(Realestate::getDescription));
break;
default:
System.out.println("Program Ended \n");
break;
}