I start the following script which I run in a bash shell(let's say shell1) in foreground and from another shell(shell2) I send the kill -SIGUSR1 pidof(scriptA). Nothing happens. What am I doing wrong ? I tried other signals(SIGQUIT etc) but the result is same.
我启动以下脚本，我在前台运行bash shell（比如说shell1），从另一个shell（shell2）运行kill -SIGUSR1 pidof（scriptA）。什么都没发生。我究竟做错了什么 ？我尝试了其他信号（SIGQUIT等）但结果是一样的。
test_trap.sh
test_trap.sh
function iAmDone { echo "Trapped Signal"; exit 0 }
trap iAmDone SIGUSR1
echo "Running... "
tail -f /dev/null # Do nothing
In shell1
在shell1中
./test_trap.sh
In shell2
在shell2中
kill -SIGUSR1 ps aux | grep [t]est_trap | awk '{print $2}'
1 个解决方案
#1
4
The trap is not executed until tail finishes. But tail never finishes. Try:
在尾部完成之前不会执行陷阱。但尾巴永远不会完成。尝试：
tail -f /dev/null &
wait
The trap will execute without waiting for tail to complete, but if you exit the tail will be left running. So you'll probably want a kill $! in the trap.
陷阱将在不等待尾部完成的情况下执行，但如果退出尾部将继续运行。所以你可能想要一个杀$！在陷阱里。
#1
4
The trap is not executed until tail finishes. But tail never finishes. Try:
在尾部完成之前不会执行陷阱。但尾巴永远不会完成。尝试：
tail -f /dev/null &
wait
The trap will execute without waiting for tail to complete, but if you exit the tail will be left running. So you'll probably want a kill $! in the trap.
陷阱将在不等待尾部完成的情况下执行，但如果退出尾部将继续运行。所以你可能想要一个杀$！在陷阱里。