I am trying to do this:
我想这样做：
{% for movie in movie_list | sort(movie.rating) %}
But that's not right...the documentation is vague...how do you do this in Jinja2?
但那不对......文档含糊不清......你怎么在Jinja2做到这一点？
3 个解决方案
#1
114
As of version 2.6, Jinja2's built-in sort filter allows you to specify an attribute to sort by:
从2.6版本开始，Jinja2的内置排序过滤器允许您指定要排序的属性：
{% for movie in movie_list|sort(attribute='rating') %}
See http://jinja.pocoo.org/docs/templates/#sort
见http://jinja.pocoo.org/docs/templates/#sort
#2
11
Usually we sort the list before giving it to Jinja2. There's no way to specify a key in Jinja's sort filter.
通常我们会在将列表提供给Jinja2之前对其进行排序。在Jinja的排序过滤器中无法指定密钥。
However, you can always try {% for movie in movie_list|sort %}. That's the syntax. You don't get to provide any sort of key information for the sorting.
但是，您可以随时尝试{％for movie in movie_list | sort％}。这就是语法。您无法为排序提供任何类型的关键信息。
You can also try and write a custom filter for this. Seems silly when you can sort before giving the data to Jinja2.
您也可以尝试为此编写自定义过滤器。在将数据提供给Jinja2之前，您可以进行排序，这似乎很愚蠢。
If movie_list is a list of objects, then you can define the various comparison methods (__lt__, __gt__, etc.) for the class of those objects.
如果movie_list是一个对象列表，那么您可以为这些对象的类定义各种比较方法（__lt __，__ gt__等）。
If movie_list is a list of tuples or lists, the rating must be first. Or you'll have to do the sorting outside Jinja2.
如果movie_list是元组或列表的列表，则必须先评级。或者你必须在Jinja2之外进行排序。
If movie_list is a list of dictionaries, then you can use dictsort, which does accept a key specification for the sorting. Read this: http://jinja.pocoo.org/2/documentation/templates#dictsort for an example.
如果movie_list是字典列表，那么您可以使用dictsort，它接受排序的密钥规范。请阅读：http：//jinja.pocoo.org/2/documentation/templates#dictsort作为示例。
#3
9
If you want to sort in ascending order
如果要按升序排序
{% for movie in movie_list|sort(attribute='rating') %}
If you want to sort in descending order
如果要按降序排序
{% for movie in movie_list|sort(attribute='rating', reverse = True) %}
#1
114
As of version 2.6, Jinja2's built-in sort filter allows you to specify an attribute to sort by:
从2.6版本开始，Jinja2的内置排序过滤器允许您指定要排序的属性：
{% for movie in movie_list|sort(attribute='rating') %}
See http://jinja.pocoo.org/docs/templates/#sort
见http://jinja.pocoo.org/docs/templates/#sort
#2
11
Usually we sort the list before giving it to Jinja2. There's no way to specify a key in Jinja's sort filter.
通常我们会在将列表提供给Jinja2之前对其进行排序。在Jinja的排序过滤器中无法指定密钥。
However, you can always try {% for movie in movie_list|sort %}. That's the syntax. You don't get to provide any sort of key information for the sorting.
但是，您可以随时尝试{％for movie in movie_list | sort％}。这就是语法。您无法为排序提供任何类型的关键信息。
You can also try and write a custom filter for this. Seems silly when you can sort before giving the data to Jinja2.
您也可以尝试为此编写自定义过滤器。在将数据提供给Jinja2之前，您可以进行排序，这似乎很愚蠢。
If movie_list is a list of objects, then you can define the various comparison methods (__lt__, __gt__, etc.) for the class of those objects.
如果movie_list是一个对象列表，那么您可以为这些对象的类定义各种比较方法（__lt __，__ gt__等）。
If movie_list is a list of tuples or lists, the rating must be first. Or you'll have to do the sorting outside Jinja2.
如果movie_list是元组或列表的列表，则必须先评级。或者你必须在Jinja2之外进行排序。
If movie_list is a list of dictionaries, then you can use dictsort, which does accept a key specification for the sorting. Read this: http://jinja.pocoo.org/2/documentation/templates#dictsort for an example.
如果movie_list是字典列表，那么您可以使用dictsort，它接受排序的密钥规范。请阅读：http：//jinja.pocoo.org/2/documentation/templates#dictsort作为示例。
#3
9
If you want to sort in ascending order
如果要按升序排序
{% for movie in movie_list|sort(attribute='rating') %}
If you want to sort in descending order
如果要按降序排序
{% for movie in movie_list|sort(attribute='rating', reverse = True) %}