如何调整代码以只删除打印所需的值

My current code:

我现在的代码:

def write_from_dict(users_folder):
    for key, value in value_dict.items():  # iterate over the dict
        file_path = os.path.join(users_folder, key + '.txt')
        with open(file_path, 'w') as f:       # open the file for writing
            for line in value:                # iterate over the lists

                f.write('{}\n'.format(line))

My current output:

我目前的输出:

['4802', '156', '4770', '141']
['4895', '157', '4810', '141']
['4923', '156', '4903', '145']

My desired output:

我的期望输出值:

4802,156,4770,141
4895,157,4810,141
4923,156,4903,145

so basically i want the spaces '' and [] removed.

所以基本上我想要删除空格和[]。

2 个解决方案

#1

Replace

取代

f.write('{}\n'.format(line))

With

与

f.write('{}\n'.format(",".join(line)))

#2

At the moment, line is a list of ints, we need to print a string which is the result of concatenating each integer (as strings) togethere with commas.

目前，line是一个ints列表，我们需要打印一个字符串，它是将每个整数(作为字符串)与逗号连接在一起的结果。

This can be done really easily with the str.join method which takes an iterable of strings and then joins them together with a deliminator - which will be a comma (',') here.

使用string .join方法可以很容易地做到这一点，该方法获取可迭代的字符串，然后将它们与一个分隔符连接在一起——这里是一个逗号('，')。

So, the f.write line should be something like:

所以,f。写行应该是这样的:

f.write('{}\n'.format(''.join(str(i) for i in line)))

or if the elements of line are already strings (it is impossible to tell from your current code), then you can use the more simple:

或者如果行元素已经是字符串(无法从当前代码中区分)，那么可以使用更简单的:

f.write('{}\n'.format(''.join(line)))

#1