I've got a data URL like this:
我有一个这样的数据网址:
data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAA...
What's the easiest way to get this as binary data (say, a Buffer
) so I can write it to a file?
最简单的方法是将它作为二进制数据(例如,缓冲区),以便将其写入文件?
3 个解决方案
#1
54
Put the data into a Buffer using the 'base64' encoding, then write this to a file:
使用'base64'编码将数据放入Buffer中,然后将其写入文件:
var fs = require('fs');
var string = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg==";
var regex = /^data:.+\/(.+);base64,(.*)$/;
var matches = string.match(regex);
var ext = matches[1];
var data = matches[2];
var buffer = new Buffer(data, 'base64');
fs.writeFileSync('data.' + ext, buffer);
#2
20
Try this
尝试这个
var dataUrl = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg==";
var buffer = new Buffer(dataUrl.split(",")[1], 'base64');
#3
3
I also met such questions (parsing and validating data URL) recently and found the following workaround: https://gist.github.com/bgrins/6194623
我最近也遇到了这样的问题(解析和验证数据URL)并找到了以下解决方法:https://gist.github.com/bgrins/6194623
I created 2 packages to make working with data URL easier in the code. Here they are: https://github.com/killmenot/valid-data-url
https://github.com/killmenot/parse-data-url
我创建了2个包,以便在代码中更轻松地处理数据URL。它们是:https://github.com/killmenot/valid-data-url https://github.com/killmenot/parse-data-url
Check out examples
查看示例
#1
54
Put the data into a Buffer using the 'base64' encoding, then write this to a file:
使用'base64'编码将数据放入Buffer中,然后将其写入文件:
var fs = require('fs');
var string = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg==";
var regex = /^data:.+\/(.+);base64,(.*)$/;
var matches = string.match(regex);
var ext = matches[1];
var data = matches[2];
var buffer = new Buffer(data, 'base64');
fs.writeFileSync('data.' + ext, buffer);
#2
20
Try this
尝试这个
var dataUrl = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg==";
var buffer = new Buffer(dataUrl.split(",")[1], 'base64');
#3
3
I also met such questions (parsing and validating data URL) recently and found the following workaround: https://gist.github.com/bgrins/6194623
我最近也遇到了这样的问题(解析和验证数据URL)并找到了以下解决方法:https://gist.github.com/bgrins/6194623
I created 2 packages to make working with data URL easier in the code. Here they are: https://github.com/killmenot/valid-data-url
https://github.com/killmenot/parse-data-url
我创建了2个包,以便在代码中更轻松地处理数据URL。它们是:https://github.com/killmenot/valid-data-url https://github.com/killmenot/parse-data-url
Check out examples
查看示例