如何在Emacs中替换一个换行符?

I am trying to replace a character - say ; - with a new line using replace-string and/or replace-regexp in Emacs.

我在试着换一个角色——说;-在Emacs中使用替换字符串和/或替换regexp的新行。

I have tried the following commands:

我试过以下命令:

M-x replace-string RET ; RET \n

m x replace-string RET;RET \ n

This will replace ; with 2 characters: \n.

这将取代;2字符:\ n。
M-x replace-regex RET ; RET \n

m x replace-regex RET;RET \ n

This results in the following error (shown in the minibuffer):

这将导致以下错误(在minibuffer中显示):

Invalid use of `\' in replacement text.

在替换文本中使用“\”无效。

What's wrong with using replace-string for this task? Is there any other way to do it?

为这个任务使用replace-string有什么问题吗?还有别的办法吗?

Thanks.

谢谢。

5 个解决方案

#1

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M-x replace-string RET ; RET C-q C-j.

m x replace-string RET;RET C-q C-j。

C-q for quoted-insert,

C-q escape,
C-j is a newline.

C-j是一个换行符。

Cheers!

干杯!

#2

There are four ways I've found to put a newline into the minibuffer.

我发现有四种方法将一条新行放入到minibuffer中。

C-o

切断
C-q C-j

C-q C-j
C-q 12 (12 is the octal value of newline)

c - q12(12是换行的八进制值)
C-x o to the main window, kill a newline with C-k, then C-x o back to the minibuffer, yank it with C-y

C-x到主窗口，用C-k杀死一条换行，然后c - xo返回到minibuffer，用C-y把它拽出来。

#3

Don't forget that you can always cut and paste into the minibuffer.

别忘了，你可以随时剪切和粘贴到minibuffer中。

So you can just copy a newline character (or any string) from your buffer, then yank it when prompted for the replacement text.

因此，您可以从缓冲区中复制一个换行符(或任何字符串)，然后在提示替换文本时将其删除。

#4

More explicitly:

更明确:

To replace the semi colon character (;) with a newline, follow these exact steps.

要用换行符替换semi冒号(;)，请遵循以下步骤。

locate cursor at upper left of buffer containing text you want to change
将光标定位在包含要更改的文本的缓冲区的左上角。
Type m-x replace-string and hit RETURN
键入m-x替换字符串并单击RETURN。
the mini-buffer will display something like this: Replace string (default ^ -> ):
微缓存将显示这样的:替换字符串(默认^ - >):
Type in the character you want to replace. In this case, ; and hit RETURN
输入要替换的字符。在这种情况下,;点击返回
the mini-buffer will display something like this: string ; with:
小缓冲区将显示如下内容:字符串;:
Now execute C-q C-j
现在执行C-q C-j
All instances of semi-colon will be replaced a newline (from the cursor location to the end of the buffer will now appear)
所有的分号实例都将被替换为一条新行(从光标位置到缓冲区的末尾将出现)

Bit more to it than the original explanation says.

比原来的解释说得多一点。

#5

Switch to text-mode

切换到文本模式

M-x text-mode

Highlight block to indent

强调块缩进

Indent

缩进

C+M \

Switch back to whatever mode..

切换回任何模式。

#1

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