I'm creating a struct that holds 3 float values,
我正在创建一个包含3个浮点值的结构,
struct Col {
var r: Float
var g: Float
var b: Float
}
and I'd like to add a bunch of function definitions that are equivalent to the built in math functions, but that operate piecewise on the members of my struct
我想添加一堆与内置数学函数等效的函数定义,但它对我的struct的成员进行分段操作
I can do it by hand, eg
我可以手工完成,例如
func pow(a: Col, b: Col) -> Col {
return Col(r: pow(a.r, b.r), g: pow(a.g, b.g), b: pow(a.b, b.b))
}
but this is tedious and error prone.
但这很乏味且容易出错。
What I'd like to do is create a function to turn the original math function into my Col version, so that I could call it like this:
我想要做的是创建一个函数将原始数学函数转换为我的Col版本,这样我就可以这样调用它:
defineColVersion(pow, noArgs: 2)
and it defines the new version, without overwriting the built in function that operates on Doubles
它定义了新版本,而不会覆盖在双打上运行的内置函数
Is there any way to do this in Swift?
在Swift中有什么办法吗?
Thanks
谢谢
3 个解决方案
#1
5
I actually think this is exactly what you want:
我实际上认为这正是你想要的:
func toCol(f: (Float, Float) -> Float) -> (Col, Col) -> Col {
return { a, b in
Col(r: f(a.r, b.r), g: f(a.g, b.g), b: f(a.b, b.b))
}
}
func toCol(f: Float -> Float) -> Col -> Col {
return { c in
Col(r: f(c.r), g: f(c.g), b: f(c.b))
}
}
let pow = toCol(Darwin.pow)
let sin = toCol(Darwin.sin)
let log = toCol(Darwin.log)
let a = Col(r: 0.4, g: 0.2, b: 0.7)
let b = Col(r: 0.3, g: 0.9, b: 0.3)
pow(a, b)
sin(a)
log(b)
The two overloaded functions toCol
take a unary/binary function on Float
s and returns a new function which does the same on your Col
type. With those two, you can easily create a pow
function for your Col
type.
两个重载函数toCol在Floats上采用一元/二元函数并返回一个新函数,它在Col类型上执行相同的操作。有了这两个,您可以轻松地为您的Col类型创建一个pow功能。
#2
3
It is not possible to programmatically define new functions in a static language like Swift. What you can do, however, is to make a higher-kinded function:
无法以编程方式在Swift等静态语言中定义新函数。但是,你可以做的是提高一个更高的功能:
func init(a: Col, b: Col, function: (Float, Float) -> Float) -> Col {
return self.init(r: function(a.r, b.r), g: function(a.g, b.g), b: function(a.b, b.b))
}
Col(Col(1, 2, 3), Col(3, 4, 5)) { $0 * $1 }
Col(Col(1, 2, 3), Col(3, 4, 5)) { pow($0, $1) }
#3
0
func init(first: Col, second: Col, function: (Float, Float) -> Float ) {
newR = function(first.r,second.r)
newG = function(first.g,second.g)
newB = function(first.b,second.b)
return self.init(r:newR,g:newG,b:newB)
}
I'm not in a position to compile this so it probably has some errors but hopefully it will be useful. You would use it like so:
我无法编译这个,所以它可能有一些错误,但希望它会有用。你会像这样使用它:
first = Col(r:1,g:2,b:3)
second = Col(r:1,g:2,b:3)
combined = Col(first:first,second:second) { pow($0,$1) }
#1
5
I actually think this is exactly what you want:
我实际上认为这正是你想要的:
func toCol(f: (Float, Float) -> Float) -> (Col, Col) -> Col {
return { a, b in
Col(r: f(a.r, b.r), g: f(a.g, b.g), b: f(a.b, b.b))
}
}
func toCol(f: Float -> Float) -> Col -> Col {
return { c in
Col(r: f(c.r), g: f(c.g), b: f(c.b))
}
}
let pow = toCol(Darwin.pow)
let sin = toCol(Darwin.sin)
let log = toCol(Darwin.log)
let a = Col(r: 0.4, g: 0.2, b: 0.7)
let b = Col(r: 0.3, g: 0.9, b: 0.3)
pow(a, b)
sin(a)
log(b)
The two overloaded functions toCol
take a unary/binary function on Float
s and returns a new function which does the same on your Col
type. With those two, you can easily create a pow
function for your Col
type.
两个重载函数toCol在Floats上采用一元/二元函数并返回一个新函数,它在Col类型上执行相同的操作。有了这两个,您可以轻松地为您的Col类型创建一个pow功能。
#2
3
It is not possible to programmatically define new functions in a static language like Swift. What you can do, however, is to make a higher-kinded function:
无法以编程方式在Swift等静态语言中定义新函数。但是,你可以做的是提高一个更高的功能:
func init(a: Col, b: Col, function: (Float, Float) -> Float) -> Col {
return self.init(r: function(a.r, b.r), g: function(a.g, b.g), b: function(a.b, b.b))
}
Col(Col(1, 2, 3), Col(3, 4, 5)) { $0 * $1 }
Col(Col(1, 2, 3), Col(3, 4, 5)) { pow($0, $1) }
#3
0
func init(first: Col, second: Col, function: (Float, Float) -> Float ) {
newR = function(first.r,second.r)
newG = function(first.g,second.g)
newB = function(first.b,second.b)
return self.init(r:newR,g:newG,b:newB)
}
I'm not in a position to compile this so it probably has some errors but hopefully it will be useful. You would use it like so:
我无法编译这个,所以它可能有一些错误,但希望它会有用。你会像这样使用它:
first = Col(r:1,g:2,b:3)
second = Col(r:1,g:2,b:3)
combined = Col(first:first,second:second) { pow($0,$1) }