Python:x-y-plot matplotlib

时间:2021-10-03 20:26:37

I want to plot some data. The first column contains the x-data. But matplotlib doesn't plot this. Where is my mistake?

我想画一些数据。第一列包含x数据。但是matplotlib并没有把它画出来。我的错误在哪里?

import numpy as np
from numpy import cos
from scipy import *
from pylab import plot, show, ylim, yticks
from matplotlib import *
from pprint import pprint

n1 = 1.0
n2 = 1.5

#alpha, beta, intensity
data = [
    [10,    22,     4.3],
    [20,    42,     4.2],
    [30,    62,     3.6],
    [40,    83,     1.3],
    [45,    102,    2.8],
    [50,    123,    3.0],
    [60,    143,    3.2],
    [70,    163,    3.8],
    ]

for i in range(len(data)):
    rhotang1 = (n1 * cos(data[i][0]) - n2 * cos(data[i][1]))
    rhotang2 = (n1 * cos(data[i][0]) + n2 * cos(data[i][1]))
    rhotang = rhotang1 / rhotang2
    data[i].append(rhotang) #append 4th value

pprint(data)
x = data[:][0]
y1 = data[:][2]
y3 = data[:][3]
plot(x, y1, x, y3)
show()

EDIT: http://paste.pocoo.org/show/205534/ But it doesn't work.

编辑:http://paste.pocoo.org/show/205534/但它不起作用。

3 个解决方案

#1


2  

x = data[:][0]
y1 = data[:][2]
y3 = data[:][3]

These lines don't do what you think.

这些台词不像你想的那样。

First they take a slice of the array which is the whole array (that is, just a copy), then they pull out the 0th, 2nd or 3rd ROW from that array, not column.

首先,他们取一个数组的一部分,这是整个数组(也就是一个拷贝),然后他们从数组中取出第0、第二或第三行,而不是列。

You could try

你可以试试

x = [row[0] for row in x]

etc.

等。

#2


5  

You can do this by converting data to a numpy array:

您可以通过将数据转换为numpy数组来实现这一点:

data = np.array(data) # insert this new line after your appends

pprint(data)
x = data[:,0]    # use the multidimensional slicing notation
y1 = data[:,2]
y3 = data[:,3]
plot(x, y1, x, y3)

A few additional points:

一些额外的点:

You can do the calculation in a more clear and vectorized way using numpy, like this

你可以用一个更清晰的矢量化的方式来计算,就像这样。

data = np.array(data)
rhotang1 = n1*cos(data[:,0]) - n2*cos(data[:,1])
rhotang2 = n1*cos(data[:,0]) + n2*cos(data[:,1])
y3 = rhotang1 / rhotang2

As you wrote it, your calculation may not give what you want since cos etc take radians as their inputs and your numbers look like degrees.

正如你写的那样,你的计算可能不会给出你想要的东西,因为等着用弧度作为它们的输入,而你的数字看起来像度数。

#3


0  

Try this:

试试这个:

#fresnel formula

import numpy as np
from numpy import cos
from scipy import *
from pylab import plot, show, ylim, yticks
from matplotlib import *
from pprint import pprint

n1 = 1.0
n2 = 1.5

#alpha, beta, intensity
data = np.array([
    [10,    22,     4.3],
    [20,    42,     4.2],
    [30,    62,     3.6],
    [40,    83,     1.3],
    [45,    102,    2.8],
    [50,    123,    3.0],
    [60,    143,    3.2],
    [70,    163,    3.8],
    ])

# Populate arrays
x = np.array([row[0] for row in data])
y1 = np.array([row[1] for row in data])
rhotang1 = n1*cos(data[:,0]) - n2*cos(data[:,1])
rhotang2 = n1*cos(data[:,0]) + n2*cos(data[:,1])
y3 = rhotang1 / rhotang2

plot(x, y1, 'r--', x, y3, 'g--')
show()

#1


2  

x = data[:][0]
y1 = data[:][2]
y3 = data[:][3]

These lines don't do what you think.

这些台词不像你想的那样。

First they take a slice of the array which is the whole array (that is, just a copy), then they pull out the 0th, 2nd or 3rd ROW from that array, not column.

首先,他们取一个数组的一部分,这是整个数组(也就是一个拷贝),然后他们从数组中取出第0、第二或第三行,而不是列。

You could try

你可以试试

x = [row[0] for row in x]

etc.

等。

#2


5  

You can do this by converting data to a numpy array:

您可以通过将数据转换为numpy数组来实现这一点:

data = np.array(data) # insert this new line after your appends

pprint(data)
x = data[:,0]    # use the multidimensional slicing notation
y1 = data[:,2]
y3 = data[:,3]
plot(x, y1, x, y3)

A few additional points:

一些额外的点:

You can do the calculation in a more clear and vectorized way using numpy, like this

你可以用一个更清晰的矢量化的方式来计算,就像这样。

data = np.array(data)
rhotang1 = n1*cos(data[:,0]) - n2*cos(data[:,1])
rhotang2 = n1*cos(data[:,0]) + n2*cos(data[:,1])
y3 = rhotang1 / rhotang2

As you wrote it, your calculation may not give what you want since cos etc take radians as their inputs and your numbers look like degrees.

正如你写的那样,你的计算可能不会给出你想要的东西,因为等着用弧度作为它们的输入,而你的数字看起来像度数。

#3


0  

Try this:

试试这个:

#fresnel formula

import numpy as np
from numpy import cos
from scipy import *
from pylab import plot, show, ylim, yticks
from matplotlib import *
from pprint import pprint

n1 = 1.0
n2 = 1.5

#alpha, beta, intensity
data = np.array([
    [10,    22,     4.3],
    [20,    42,     4.2],
    [30,    62,     3.6],
    [40,    83,     1.3],
    [45,    102,    2.8],
    [50,    123,    3.0],
    [60,    143,    3.2],
    [70,    163,    3.8],
    ])

# Populate arrays
x = np.array([row[0] for row in data])
y1 = np.array([row[1] for row in data])
rhotang1 = n1*cos(data[:,0]) - n2*cos(data[:,1])
rhotang2 = n1*cos(data[:,0]) + n2*cos(data[:,1])
y3 = rhotang1 / rhotang2

plot(x, y1, 'r--', x, y3, 'g--')
show()