A new day brought new problem with Python, unfortunately :/
新的一天给Python带来了新的问题，不幸的是:/
I have a file generated by my other app written in Java. This app generates files with some data, it's kind a random stuff 'cause I'm not able to say how many rows each file would have. Example file looks like this:
我有一个由我的另一个用Java编写的应用程序生成的文件。这个应用会生成一些数据，这是随机的，因为我不知道每个文件有多少行。示例文件如下所示:
3 Sat Jan 21 00:00:00 2012
7 Sun Mar 11 00:00:00 2012
5 Fri Jan 1 00:00:00 2010
4 Sat Feb 5 00:00:00 2011
8 Sun Apr 11 00:00:00 2010
4 Wed Aug 24 00:00:00 2011
8 Sat Feb 20 00:00:00 2010
3 Thu Oct 13 00:00:00 2011
9 Fri Dec 17 00:00:00 2010
4 Tue Jul 20 00:00:00 2010
8 Fri Dec 2 00:00:00 2011
6 Mon May 31 00:00:00 2010
5 Mon May 16 00:00:00 2011
8 Mon Apr 30 00:00:00 2012
3 Thu Oct 28 00:00:00 2010
1 Tue Jun 19 00:00:00 2012
7 Wed Sep 8 00:00:00 2010
And I want to draw a chart with use of this data. On X axis I would like to have formatted dates, and on Y axis numbers from the first column of my file. Heres my lovely python code:
我想用这些数据画一个图表。在X轴上我想要格式化日期，在Y轴上我文件第一列的数字。下面是我可爱的python代码:
# -*- coding: utf-8 -*-
#!/usr/bin/env python
import wx
import matplotlib
matplotlib.use("TkAgg")
import matplotlib.pyplot as pl
import datetime
def monthNum(month) :
if month == "Jan" :
return 1
elif month == "Feb" :
return 2
elif month == "Mar" :
return 3
elif month == "Apr" :
return 4
elif month == "May" :
return 5
elif month == "Jun" :
return 6
elif month == "Jul" :
return 7
elif month == "Aug" :
return 8
elif month == "Sep" :
return 9
elif month == "Oct" :
return 10
elif month == "Nov" :
return 11
elif month == "Dec" :
return 12
def convertDate(dateTime) :
line = dateTime.split(' ')
date = (str(line[2]) + "-" + str(monthNum(line[1])) + "-" + str(line[4]))
return date
def readFile(filename) :
values = []
dates = []
try :
with open(filename, "r") as openedFile:
for line in openedFile :
line = line.strip()
data = line.split("\t")
values.append(int(data[0]))
newDate = convertDate(data[1])
dates.append(datetime.datetime.strptime(newDate, "%d-%m-%Y").date())
except IOError :
print("IOERROR")
except ValueError :
print("VALUE ERROR")
if len(values) != 0 and len(dates) != 0 :
drawChart(values, dates, filename)
def drawChart(values, dates, filename):
fig = pl.figure(dpi=60,figsize=(18, 10))
ax = fig.add_subplot(1,1,1)
fig.subplots_adjust(left=0.1, right=0.95, top=0.95, bottom=0.2)
ax.bar(range(len(dates)), values, facecolor='#777777', align='center', width=0.5, ecolor='black')
pl.axis('tight')
ax.set_xticks(range(len(dates)))
pl.yticks(values)
ax.set_xticklabels(dates, rotation = 90)
pl.savefig(filename + ".png")
pl.show()
pl.close()
readFile("file.txt")
Everything is fine, if file.txt had a one, single row. When it has more rows, python code gives me an error:
一切都很好，如果文件。txt有一个单行。当它有更多行时，python代码会给我一个错误:
VALUE ERROR Traceback (most recent call last): File "test.py", line 71, in <module> readFile("file.txt") File "test.py", line 56, in readFile drawChart(values, dates, filename) File "test.py", line 62, in drawChart ax.bar(range(len(dates)), values, facecolor='#777777', align='center', width=0.5, ecolor='black') File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 4733, in bar nbars) AssertionError: incompatible sizes: argument 'height' must be length 2 or scalar
And I don't really know how to fix it. Its fine, if file.txt had one row but as I wrote earlier: I'm not able to say how many rows would file.txt have (it depends on my Java app).
我也不知道怎么修理。它的好,如果文件。txt有一行，但正如我前面所写的:我不能说出要文件多少行。txt有(这取决于我的Java应用)。
Anybody? I use Python 2.7 and Matplotlib on Kubuntu 12.04.
有人知道吗?我在kubuntu12.04上使用Python 2.7和Matplotlib。
2 个解决方案
#1
12
It's because dates only has 2 values. The length of dates and the length of values must be the same for matplotlib to know what to do. If values was a scalar then all the bars would have the same height
因为日期只有两个值。对于matplotlib来说，日期的长度和值的长度必须是相同的，这样才能知道要做什么。如果值是标量，那么所有的条都有相同的高度
#2
1
Thanks I think I figured it out - the problem was with the readFile(arg) function, it should look like this:
谢谢，我想我算出来了——问题是readFile(arg)函数，应该是这样的:
def readFile(filename) :
values = []
dates = []
openedFile = open(filename, "r")
content = openedFile.readlines()
openedFile.close()
for line in content :
line = line.strip()
data = line.split("\t")
values.append(int(data[0]))
newDate = self.convertDate(data[1])
dates.append(newDate)
print(values)
print(dates)
#1
12
It's because dates only has 2 values. The length of dates and the length of values must be the same for matplotlib to know what to do. If values was a scalar then all the bars would have the same height
因为日期只有两个值。对于matplotlib来说，日期的长度和值的长度必须是相同的，这样才能知道要做什么。如果值是标量，那么所有的条都有相同的高度
#2
1
Thanks I think I figured it out - the problem was with the readFile(arg) function, it should look like this:
谢谢，我想我算出来了——问题是readFile(arg)函数，应该是这样的:
def readFile(filename) :
values = []
dates = []
openedFile = open(filename, "r")
content = openedFile.readlines()
openedFile.close()
for line in content :
line = line.strip()
data = line.split("\t")
values.append(int(data[0]))
newDate = self.convertDate(data[1])
dates.append(newDate)
print(values)
print(dates)