I am trying to match a group in regex but I don't want this group to be in the final result.
我正在尝试匹配正则表达式中的一个组,但我不希望这个组在最终结果中。
For example:
((kl(\.)?|at)?([0-1][0-9]|2[0-3]):[0-5][0-9](:[0-5][0-9])?)
Running the above expression on at 12:25 should return 12:25.
在12:25运行上面的表达式应该返回12:25。
Is there any way to do this?
有没有办法做到这一点?
I tried using:
我试过用:
(?:((kl(\.)?|at)? )([0-1][0-9]|2[0-3]):[0-5][0-9](:[0-5][0-9])?)
But that's no difference.
但这没什么区别。
Then I tried
然后我试了一下
(?<!(?:((kl(\.)?|at)? )([0-1][0-9]|2[0-3]):[0-5][0-9](:[0-5][0-9])?)
But that returned an empty result.
但那返回了一个空洞的结果。
I am using the expression in C#.
我在C#中使用表达式。
1 个解决方案
#1
9
A non-capturing group (not found in the match groups) is denoted as (?:). So,
非捕获组(在匹配组中找不到)表示为(?:)。所以,
(?:(?:kl(?:\.)?|at)?([0-1][0-9]|2[0-3]):[0-5][0-9](:[0-5][0-9])?)
But you regexp seems to be wrongly structured from the outset. You don't capture the minutes.
但是你的regexp似乎从一开始就是错误的结构。你没有抓住会议记录。
#1
9
A non-capturing group (not found in the match groups) is denoted as (?:). So,
非捕获组(在匹配组中找不到)表示为(?:)。所以,
(?:(?:kl(?:\.)?|at)?([0-1][0-9]|2[0-3]):[0-5][0-9](:[0-5][0-9])?)
But you regexp seems to be wrongly structured from the outset. You don't capture the minutes.
但是你的regexp似乎从一开始就是错误的结构。你没有抓住会议记录。