在Python Selenium中通过xPath定位表元素

I copied the xPath of a certain element I am trying to click and obtained the following:

我复制了我想要点击的某个元素的xPath，并获得了以下内容：

//*[@id="ctl00_ctl00_ctl00_body_homebody_PageMainContent_ResultsGrid_ctl00__0"]/td[1]/a

My code then contains the following:

然后我的代码包含以下内容：

driver.find_element_by_id("//*[@id="ctl00_ctl00_ctl00_body_homebody_PageMainContent_ResultsGrid_ctl00__0"]/td[1]/a").click()

Any idea why I might be getting this error: r aise exception_class(message, screen, stacktrace) selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element

知道为什么我可能会收到此错误：r aise exception_class（message，screen，stacktrace）selenium.common.exceptions.NoSuchElementException：消息：没有这样的元素：无法定位元素

1 个解决方案

#1

XPATHs may contain id (or many other HTML tags), but that does not mean that the id is the XPATH. Use:

XPATH可能包含id（或许多其他HTML标记），但这并不意味着id是XPATH。使用：

driver.find_element_by_xpath('//*[@id="ctl00_ctl00_ctl00_body_homebody_PageMainContent_ResultsGrid_ctl00__0"]/td[1]/a').click()

and it should work - assuming there is a valid XPATH at that location on your website.

它应该工作 - 假设您的网站上的该位置有一个有效的XPATH。

also, re: your comment on the OP - //* specifies relative XPATH vs absolute XPATH - essentially meaning that it skips the initial and tags and goes straight to the middle of the DOM.

另外，你对OP的评论 - // *指定相对XPATH与绝对XPATH - 本质上意味着它跳过了初始和标签并直接进入DOM的中间。

#1