Java字符串删除所有非数字字符

Trying to remove all letters and characters that are not 0-9 and a period. I'm using Character.isDigit() but it also removes decimal, how can I also keep the decimal?

试图删除所有非0-9和一个句点的字母和字符。我用的是字符。isdigit()但它也去掉了小数，我怎么能保留小数点呢?

8 个解决方案

#1

395

Try this code:

试试这段代码:

String str = "a12.334tyz.78x";
str = str.replaceAll("[^\\d.]", "");

Now str will contain "12.334.78".

现在str将包含“12.334.78”。

#2

I would use a regex.

我会使用正则表达式。

String text = "-jaskdh2367sd.27askjdfh23";
String digits = text.replaceAll("[^0-9.]", "");
System.out.println(digits);

prints

打印

2367.2723

You might like to keep - as well for negative numbers.

你可能想保留-对于负数也一样。

#3

String phoneNumberstr = "Tel: 00971-557890-999";
String numberRefined = phoneNumberstr.replaceAll("[^\\d-]", "");

result: 0097-557890-999

结果:0097-557890-999

if you also do not need "-" in String you can do like this:

如果你也不需要“-”字符串你可以这样做:

String phoneNumberstr = "Tel: 00971-55 7890 999";      
String numberRefined = phoneNumberstr.replaceAll("[^0-9]", "");

result: 0097557890999

结果:0097557890999

#4

With guava:

番石榴:

String input = "abx123.5";
String result = CharMatcher.inRange('0', '9').or(CharMatcher.is('.')).retainFrom(input);

see http://code.google.com/p/guava-libraries/wiki/StringsExplained

参见http://code.google.com/p/guava-libraries/wiki/StringsExplained

#5

str = str.replaceAll("\\D+","");

#6

Simple way without using Regex:

不使用正则表达式的简单方法:

Adding an extra character check for dot '.' will solve the requirement:

为点添加额外的字符检查。将解决以下要求:

public static String getOnlyNumerics(String str) {
    if (str == null) {
        return null;
    }
    StringBuffer strBuff = new StringBuffer();
    char c;
    for (int i = 0; i < str.length() ; i++) {
        c = str.charAt(i);
        if (Character.isDigit(c) || c == '.') {
            strBuff.append(c);
        }
    }
    return strBuff.toString();
}

#7

Currency decimal separator can be different from Locale to another. It could be dangerous to consider . as separator always. i.e.

不同地区的货币小数分隔符可以不同。考虑它可能是危险的。作为分隔符。即。

╔════════════════╦═══════════════════╗
║    Currency    ║      Sample       ║
╠════════════════╬═══════════════════╣
║ USA            ║ $1,222,333.44 USD ║
║ United Kingdom ║ £1.222.333,44 GBP ║
║ European       ║ €1.333.333,44 EUR ║
╚════════════════╩═══════════════════╝

I think the proper way is:

我认为正确的方法是:

Get decimal character via DecimalFormatSymbols by default Locale or specified one.
通过缺省语言环境或指定语言环境通过DecimalFormatSymbols获取十进制字符。
Cook regex pattern with decimal character in order to obtain digits only
用十进制字符烹调regex模式，以便只获得数字

And here how I am solving it:

我是这样解决的:

import java.text.DecimalFormatSymbols;
import java.util.Locale;

进口java.text.DecimalFormatSymbols;进口java.util.Locale;

code:

代码:

    public static String getDigit(String quote, Locale locale) {
    char decimalSeparator;
    if (locale == null) {
        decimalSeparator = new DecimalFormatSymbols().getDecimalSeparator();
    } else {
        decimalSeparator = new DecimalFormatSymbols(locale).getDecimalSeparator();
    }

    String regex = "[^0-9" + decimalSeparator + "]";
    String valueOnlyDigit = quote.replaceAll(regex, "");
    try {
        return valueOnlyDigit;
    } catch (ArithmeticException | NumberFormatException e) {
        Log.e(TAG, "Error in getMoneyAsDecimal", e);
        return null;
    }
    return null;
}

I hope that may help,'.

我希望这能有所帮助。

#8

A way to replace it with a java 8 stream:

用java 8流替换它的方法:

public static void main(String[] args) throws IOException
{
    String test = "ab19198zxncvl1308j10923.";
    StringBuilder result = new StringBuilder();

    test.chars().mapToObj( i-> (char)i ).filter( c -> Character.isDigit(c) || c == '.' ).forEach( c -> result.append(c) );

    System.out.println( result ); //returns 19198.130810923.
}

#1

395