在Python 2.4中，如何在';'之后删除字符？

Let's say I'm parsing a file, which uses ; as the comment character. I don't want to parse comments. So if I a line looks like this:

假设我正在解析一个使用的文件;作为评论字符。我不想解析评论。所以,如果我的一行看起来像这样:

example.com.              600     IN      MX      8 s1b9.example.net ; hello!

Is there an easier/more-elegant way to strip chars out other than this:

是否有一种更容易/更优雅的方法来剥离除此之外的字符:

rtr = ''
for line in file:
    trig = False
    for char in line:
        if not trig and char != ';':
            rtr += char
        else:
            trig = True
    if rtr[max(rtr)] != '\n':
        rtr += '\n'

8 个解决方案

#1

I'd recommend saying

我建议说

line.split(";")[0]

which will give you a string of all characters up to but not including the first ";" character. If no ";" character is present, then it will give you the entire line.

它将为您提供一系列所有字符,但不包括第一个“;”字符。如果不 ”;”字符存在,然后它会给你整行。

#2

just do a split on the line by comment then get the first element eg

只需通过注释进行分割,然后获取第一个元素,例如

line.split(";")[0]

#3

For Python 2.5 or greater, I would use the partition method:

对于Python 2.5或更高版本,我将使用分区方法:

rtr = line.partition(';')[0].rstrip() + '\n'

#4

file = open(r'c:\temp\test.txt', 'r')
for line in file:   print
   line.split(";")[0].strip()

#5

So you'll want to split the line on the first semicolon, take everything before it, strip off any lingering whitespace, and append a newline character.

因此,您需要在第一个分号上拆分该行,将所有内容分开,删除任何延迟的空格,然后附加换行符。

rtr = line.split(";", 1)[0].rstrip() + '\n'

Links to Documentation:

文档链接:

split
rstrip

#6

Reading, splitting, stripping, and joining lines with newline all in one line of python:

在一行python中读取,拆分,剥离和连接换行符:

rtr = '\n'.join(line.split(';')[0].strip() for line in open(r'c:\temp\test.txt', 'r'))

#7

Here is another way :

这是另一种方式:

In [6]: line = "foo;bar"
In [7]: line[:line.find(";")] + "\n"
Out[7]: 'foo\n'

#8

-2

I have not tested this with python but I use similar code else where.

我没有用python测试过这个,但我在其他地方使用了类似的代码。

import re
content = open(r'c:\temp\test.txt', 'r').read()
content = re.sub(";.+", "\n")

#1