In my code I need to substitute ALL the expressions of sin(g(t)) (g being a continuous function) to g(t) (it's the tight angle approximation). This is a sample of what I get from my code:
在我的代码中，我需要将sin（g（t））的所有表达式（g是连续函数）替换为g（t）（它是紧密角度近似）。这是我从代码中获得的一个示例：
-29.4*sin(2*t) - 19.6*sin(f(t)) + 4.0*Derivative(f(t), t)**2
I need to substitute both sin(f(t)) and sin(2*t). Not just one of them and sin(2*t) changes, (sin(f(t)) is always the same). Is there a simpler way than adding an extra variable for what's inside the sin or isn't there?
我需要替换sin（f（t））和sin（2 * t）。不仅仅是其中一个和sin（2 * t）的变化，（sin（f（t））总是相同的）。有没有比为罪中的内容添加额外变量更简单的方法还是不存在？
1 个解决方案
#1
5
Is this what you are trying to do?
这是你想要做的吗？
import sympy as sp
t = sp.symbols('t')
f = sp.Function('f')
expr_v1 = -29.4*sp.sin(2*t) - 19.6*sp.sin(f(t)) + 4.0*sp.Derivative(f(t), t)**2
print('expr_v1 = ', expr_v1)
expr_v2 = expr_v1.replace(sp.sin, lambda *args: args[0])
print('expr_v2 = ', expr_v2)
expr_v1 = -29.4*sin(2*t) - 19.6*sin(f(t)) + 4.0*Derivative(f(t),t)**2 expr_v2 = -58.8*t - 19.6*f(t) + 4.0*Derivative(f(t), t)**2
#1
5
Is this what you are trying to do?
这是你想要做的吗？
import sympy as sp
t = sp.symbols('t')
f = sp.Function('f')
expr_v1 = -29.4*sp.sin(2*t) - 19.6*sp.sin(f(t)) + 4.0*sp.Derivative(f(t), t)**2
print('expr_v1 = ', expr_v1)
expr_v2 = expr_v1.replace(sp.sin, lambda *args: args[0])
print('expr_v2 = ', expr_v2)
expr_v1 = -29.4*sin(2*t) - 19.6*sin(f(t)) + 4.0*Derivative(f(t),t)**2 expr_v2 = -58.8*t - 19.6*f(t) + 4.0*Derivative(f(t), t)**2