MbUnit：比较双打最优雅的方式？

The code

Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude);

produces

Expected Value & Actual Value : 9.97320998018748
Remark : Both values look the same when formatted but they 
are distinct instances.

What is the most elegant way to compare two doubles for equality in MbUnit 3.0? I know I could round them up myself, but is there some MbUnit construct for this?

在MbUnit 3.0中比较两个双重同等的最优雅的方法是什么?我知道我可以自己围绕它们,但是有一些MbUnit构造吗?

UPDATE: I consider my current "workaround" to be non-elegant:

更新:我认为我目前的“解决方法”不优雅:

Assert.LessThan(
   Math.Abs(9.97320998018748d - observerPosition.CenterLongitude),
   0.0000001);

1 个解决方案

#1

AreApproximatelyEqual seems to be the "MbUnit construct for this":

AreApproximatelyEqual似乎是“MbUnit构造的”:

Verifies that an actual value approximately equals some expected value to within a specified delta.

验证实际值是否大约等于指定增量内的某些预期值。

This seems to be similar to Assert.AreEqual(double expected, double actual, double delta)

这似乎与Assert.AreEqual类似(双重预期,双重实际,双三角形)

#1