My dictionary looks like this(Dictionary within a dictionary):
我的字典是这样的(字典里的字典):
{'0': {'chosen_unit': , 'cost': Decimal('10.0000'), 'unit__name_abbrev': u'G', 'supplier_supplier': u"Steve's Meat Locker", 'price': Decimal('5.00'), 'supplier_address': u'No\r\naddress here', 'chosen_unit_amount': u'2', 'city_name': u'Joburg, Central', 'supplier_phone_number': u'02299944444', 'supplier_website': None, 'supplier_price_list': u'', 'supplier_email': u'ss.sss@ssssss.com', 'unit_name': u'Gram', 'name': u'Rump Bone'}}
{' style ' font - family: " tahoma ", " sans - serif "; mso - fareast - font - family:宋体;mso - bidi - font - family: " times new roman "; mso - bidi - theme - font: minor - bidi ' > < span
Now I'm just trying to display the information on my template but I'm struggling. My code for the template looks like:
现在我只是想在模板上显示信息,但是我很纠结。我的模板代码如下:
{% if landing_dict.ingredients %}
<hr>
{% for ingredient in landing_dict.ingredients %}
{{ ingredient }}
{% endfor %}
<a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
Please search for an ingredient below
{% endif %}
It just shows me '0' on my template?
它只是在模板上显示'0' ?
I also tried:
我也试过:
{% for ingredient in landing_dict.ingredients %}
{{ ingredient.cost }}
{% endfor %}
This doesn't even display a result.
这甚至不会显示结果。
I thought perhaps I need to iterate one level deeper so tried this:
我想也许我需要更深入地重复一个层次,所以我尝试了这个:
{% if landing_dict.ingredients %}
<hr>
{% for ingredient in landing_dict.ingredients %}
{% for field in ingredient %}
{{ field }}
{% endfor %}
{% endfor %}
<a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
Please search for an ingredient below
{% endif %}
But this doesn't display anything.
但是这个没有显示任何东西。
What am I doing wrong?
我做错了什么?
1 个解决方案
#1
174
Lets say your data is -
假设你的数据是-
data = {'a': [ [1, 2] ], 'b': [ [3, 4] ],'c':[ [5,6]] }
data = { a:[[1,2]],b:[[3,4]],“c”:[[5,6]]}
You can use the data.items()
method to get the dictionary elements. Note, in django templates we do NOT put ()
. Also some users mentioned values[0]
does not work, if that is the case then try values.items
.
可以使用data.items()方法获取字典元素。注意,在django模板中我们不放置()。还有一些用户提到的值[0]不起作用,如果是这样,请尝试values.items。
<table>
<tr>
<td>a</td>
<td>b</td>
<td>c</td>
</tr>
{% for key, values in data.items %}
<tr>
<td>{{key}}</td>
{% for v in values[0] %}
<td>{{v}}</td>
{% endfor %}
</tr>
{% endfor %}
</table>
Am pretty sure you can extend this logic to your specific dict.
我非常确信您可以将这种逻辑扩展到您的特定命令。
To iterate over dict keys in a sorted order - First we sort in python then iterate & render in django template.
要以排序的顺序遍历字典键——首先在python中排序,然后在django模板中迭代和呈现。
return render_to_response('some_page.html', {'data': sorted(data.items())})
返回render_to_response(some_page。html的,{“数据”:排序(data.items())})
In template file:
在模板文件:
{% for key, value in data %}
<tr>
<td> Key: {{ key }} </td>
<td> Value: {{ value }} </td>
</tr>
{% endfor %}
#1
174
Lets say your data is -
假设你的数据是-
data = {'a': [ [1, 2] ], 'b': [ [3, 4] ],'c':[ [5,6]] }
data = { a:[[1,2]],b:[[3,4]],“c”:[[5,6]]}
You can use the data.items()
method to get the dictionary elements. Note, in django templates we do NOT put ()
. Also some users mentioned values[0]
does not work, if that is the case then try values.items
.
可以使用data.items()方法获取字典元素。注意,在django模板中我们不放置()。还有一些用户提到的值[0]不起作用,如果是这样,请尝试values.items。
<table>
<tr>
<td>a</td>
<td>b</td>
<td>c</td>
</tr>
{% for key, values in data.items %}
<tr>
<td>{{key}}</td>
{% for v in values[0] %}
<td>{{v}}</td>
{% endfor %}
</tr>
{% endfor %}
</table>
Am pretty sure you can extend this logic to your specific dict.
我非常确信您可以将这种逻辑扩展到您的特定命令。
To iterate over dict keys in a sorted order - First we sort in python then iterate & render in django template.
要以排序的顺序遍历字典键——首先在python中排序,然后在django模板中迭代和呈现。
return render_to_response('some_page.html', {'data': sorted(data.items())})
返回render_to_response(some_page。html的,{“数据”:排序(data.items())})
In template file:
在模板文件:
{% for key, value in data %}
<tr>
<td> Key: {{ key }} </td>
<td> Value: {{ value }} </td>
</tr>
{% endfor %}