I capture the string from a html source file using regex:
我使用regex从html源文件捕获字符串:
f = open(rrfile, 'r')
p = re.compile(r'"name":"([^"]+)","head":"([^"]+)"')
match = re.findall(p, f.read())
And I've tried:
我已经试过:
>>> u'\\u4f60\\u4f60'.replace('\\u', '\u')
u'\\u4f60\\u4f60'
>>> u'\\u4f60\\u4f60'.replace(u'\\u', '\u')
u'\\u4f60\\u4f60'
>>> u'\\u4f60\\u4f60'.replace('\\u', u'\u')
File "<stdin>", line 1
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: end of string in escape sequence
Could that be done by str.replace()? Or need something more complex?
可以用str.replace()来完成吗?还是需要更复杂的东西?
1 个解决方案
#1
6
>>> u'\\u4f60\\u4f60'.decode('unicode_escape')
u'\u4f60\u4f60'
#1
6
>>> u'\\u4f60\\u4f60'.decode('unicode_escape')
u'\u4f60\u4f60'