在Python中Url解码UTF-8。

I have spent plenty of time as far as I am newbie in Python.
How could I ever decode such a URL:

我花了很多时间在Python里，我是新手。我怎么能解码这样一个URL:

example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0

to this one in python 2.7: example.com?title==правовая+защита

在python 2.7:example.com ?标题= =правовая+защита

url=urllib.unquote(url.encode("utf8")) is returning something very ugly.

url=urllib.unquote(url.encode("utf8"))返回非常丑陋的东西。

Still no solution, any help is appreciated.

仍然没有解决办法，任何帮助都是值得感激的。

2 个解决方案

#1

247

The data is UTF-8 encoded bytes escaped with URL quoting, so you want to decode:

数据是UTF-8编码的字节通过URL引用转义，所以你要解码:

url = urllib.unquote(url).decode('utf8')

Demo:

演示:

>>> import urllib 
>>> url='example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0'
>>> urllib.unquote(url).decode('utf8') 
u'example.com?title=\u043f\u0440\u0430\u0432\u043e\u0432\u0430\u044f+\u0437\u0430\u0449\u0438\u0442\u0430'
>>> print urllib.unquote(url).decode('utf8')
example.com?title=правовая+защита

The Python 3 equivalent is urllib.parse.unquote(), which by default handles decoding for you:

Python 3的等效项是urllib.parse.unquote()，它默认为您处理译码:

from urllib.parse import unquote

url = unquote(url)

#2

101

If you are using Python 3, you can use urllib.parse

如果您使用的是python3，您可以使用urllib.parse。

url = """example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0"""

import urllib.parse
urllib.parse.unquote(url)

gives:

给:

'example.com?title=правовая+защита'

#1

247