how to convert a string to UTF-16 in java ?
如何在java中将字符串转换为UTF-16?
i am converting the below objc code to java , but the java code does not give me same result as this code
我正在将下面的objc代码转换为java,但java代码并没有给我与此代码相同的结果
NSData *inputData = [pm dataUsingEncoding:NSUTF16LittleEndianStringEncoding];
NSString *encodedString = [inputData base64EncodedString];
pm = [IFunctions replaceString:encodedString replaceChar:@"=" replaceWithChar:@"-"];
Java code
String s_decoded = new String(pm.getBytes(), "UTF-16LE");
pm = Base64.encode(s_decoded.getBytes()).toString().replace("=", "-");
4 个解决方案
#1
The no-arg getBytes() method uses the platform default encoding, which is probably not UTF-16LE. Try getBytes("UTF-16LE")
.
no-arg getBytes()方法使用平台默认编码,该编码可能不是UTF-16LE。试试getBytes(“UTF-16LE”)。
#2
byte[] bytesEncoded = Base64.encodeBase64(str.getBytes("UTF-16LE"));
String stringEncoded = new String(bytesEncoded);
#3
Refer to this code and modify yours.
请参阅此代码并修改您的代码。
public class UseTheForce {
public static void main(final String[] args)
throws java.io.UnsupportedEncodingException {
for (final byte b : args[0].getBytes(args[1])) {
System.out.printf("%1$02X ", (b & 0xFF));
}
System.out.println();
}
}
Test
$ java UseTheForce luke US-ASCII
6C 75 6B 65
$ java UseTheForce luke UTF-8
6C 75 6B 65
$ java UseTheForce luke UTF-16
FE FF 00 6C 00 75 00 6B 00 65
$ java UseTheForce luke UTF-16BE
00 6C 00 75 00 6B 00 65
$ java UseTheForce luke UTF-16LE
6C 00 75 00 6B 00 65 00
$ java UseTheForce luke UTF-32
00 00 00 6C 00 00 00 75 00 00 00 6B 00 00 00 65
#4
You need to use getBytes()
method and specify desired charset:
您需要使用getBytes()方法并指定所需的字符集:
public static void main(String[] args) throws UnsupportedEncodingException {
char ch;
ch = 0x0001;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
ch = 0x0111;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
ch = 0x1111;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
}
Output:
[1, 0]
[17, 1]
[17, 17]
#1
The no-arg getBytes() method uses the platform default encoding, which is probably not UTF-16LE. Try getBytes("UTF-16LE")
.
no-arg getBytes()方法使用平台默认编码,该编码可能不是UTF-16LE。试试getBytes(“UTF-16LE”)。
#2
byte[] bytesEncoded = Base64.encodeBase64(str.getBytes("UTF-16LE"));
String stringEncoded = new String(bytesEncoded);
#3
Refer to this code and modify yours.
请参阅此代码并修改您的代码。
public class UseTheForce {
public static void main(final String[] args)
throws java.io.UnsupportedEncodingException {
for (final byte b : args[0].getBytes(args[1])) {
System.out.printf("%1$02X ", (b & 0xFF));
}
System.out.println();
}
}
Test
$ java UseTheForce luke US-ASCII
6C 75 6B 65
$ java UseTheForce luke UTF-8
6C 75 6B 65
$ java UseTheForce luke UTF-16
FE FF 00 6C 00 75 00 6B 00 65
$ java UseTheForce luke UTF-16BE
00 6C 00 75 00 6B 00 65
$ java UseTheForce luke UTF-16LE
6C 00 75 00 6B 00 65 00
$ java UseTheForce luke UTF-32
00 00 00 6C 00 00 00 75 00 00 00 6B 00 00 00 65
#4
You need to use getBytes()
method and specify desired charset:
您需要使用getBytes()方法并指定所需的字符集:
public static void main(String[] args) throws UnsupportedEncodingException {
char ch;
ch = 0x0001;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
ch = 0x0111;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
ch = 0x1111;
System.out.println(Arrays.toString((String.valueOf(ch)).getBytes(StandardCharsets.UTF_16LE)));
}
Output:
[1, 0]
[17, 1]
[17, 17]