i dont know much about regular expressions and from what i'v learned i cant solve my entire problem.
我不太了解正则表达式,从我学到的东西我无法解决我的整个问题。
I have this String:
我有这个字符串:
04 credits between subjects of block 02
02区块的主题之间有04学分
I'm only sure i will have [00-99] on the beggining and at end.
我只相信我会在开始时有[00-99]。
I wanna capture the beggining and the end IF the middle has "credits between", the system can have other formats as input, so i wanna be sure that these fields captured will go from the correct pattern.
我想捕获开始和结束如果中间有“信用之间”,系统可以有其他格式作为输入,所以我想确保捕获的这些字段将来自正确的模式。
This is what i'v tried to do:
这就是我试图做的事情:
(\w\w) ^credits between$.+ (\w\w)
I'm using the Regexr website to see what i'm doing, but no success.
我正在使用Regexr网站查看我在做什么,但没有成功。
1 个解决方案
#1
2
You may use the following regex:
您可以使用以下正则表达式:
^(\d{2})\b.*credits between.*\b(\d{2})$
See regex demo
请参阅正则表达式演示
It will match and capture 2 digits at the beginning and end if the string itself contains credits between. Note that newlines can be supported with [\s\S] instead of ..
如果字符串本身包含信用,它将匹配并捕获开头和结尾的2位数字。请注意,可以使用[\ s \ S]而不是..来支持换行符。
The word boundaries \b just make the engine match the digits followed by a non-word character (you may remove it if that is not expected behavior). Then, you'd need to use ^(\d{2})\b.*credits between.*?(\d{2})$ with the lazy matching .*? at the end.
单词boundary \ b只是使引擎匹配数字后跟非单词字符(如果不是预期的行为,你可以删除它)。然后,你需要在。*?(\ d {2})$之间使用^(\ d {2})\ b。*信用与懒惰匹配。*?最后。
If the number of digits in the numbers at both ends can vary, just use
如果两端数字的位数可以变化,只需使用
^(\d+).*credits between.*?(\d+)$
See another demo
看另一个演示
#1
2
You may use the following regex:
您可以使用以下正则表达式:
^(\d{2})\b.*credits between.*\b(\d{2})$
See regex demo
请参阅正则表达式演示
It will match and capture 2 digits at the beginning and end if the string itself contains credits between. Note that newlines can be supported with [\s\S] instead of ..
如果字符串本身包含信用,它将匹配并捕获开头和结尾的2位数字。请注意,可以使用[\ s \ S]而不是..来支持换行符。
The word boundaries \b just make the engine match the digits followed by a non-word character (you may remove it if that is not expected behavior). Then, you'd need to use ^(\d{2})\b.*credits between.*?(\d{2})$ with the lazy matching .*? at the end.
单词boundary \ b只是使引擎匹配数字后跟非单词字符(如果不是预期的行为,你可以删除它)。然后,你需要在。*?(\ d {2})$之间使用^(\ d {2})\ b。*信用与懒惰匹配。*?最后。
If the number of digits in the numbers at both ends can vary, just use
如果两端数字的位数可以变化,只需使用
^(\d+).*credits between.*?(\d+)$
See another demo
看另一个演示