sed: -e表达式#1,char 23:未知选项为' s'[复制]

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sed - unknown option to `s' 1 answer
sed -未知选项为' s'的答案。

I'm trying to use sed to update a config file using a bash script. I have a similar sed command right above this one in the script that runs fine. I can't seem to figure out why this is breaking:

我尝试使用sed来使用bash脚本更新配置文件。在运行良好的脚本中，我有一个类似的sed命令。我似乎弄不明白为什么会这样:

sed -i.bak \
    -e s/"socketPath:'https://localhost:9091'"/"socketPath:'/socket'"/g \
    $WEB_CONF

Any ideas?

什么好主意吗?

3 个解决方案

#1

The quotes and double quotes are causing problems. You are using them in view of the slashes in the string. In sed you can use another delimiter, such as a #.

引号和双引号引起了问题。您使用它们是为了查看字符串中的斜线。在sed中，可以使用另一个分隔符，例如#。

sed -e 's#socketPath:https://localhost:9091#socketPath:/socket#g' \
$WEB_CONF

#2

Escape your slashes in the pattern or use a different delimiter like this:

在模式中跳出您的斜线，或者使用如下的分隔符:

sed -i.bak \
-e s%"socketPath:'https://localhost:9091'"%"socketPath:'/socket'"%g \
$WEB_CONF

#3

I am confused looking at the delimiters you have used so you can't blame sed for goofing up. When your dataset has / in them, it is often advised to use a different delimiters like # or _ (yes, sed supports various delimiters).

我对你使用过的分隔符感到困惑，所以你不能怪它搞砸了。当您的数据集/在它们中时，通常建议使用不同的分隔符，比如#或_(是的，sed支持各种分隔符)。

Also, your quoting looks abit off. The syntax should be:

而且，你的引文看起来也不一样。语法应该是:

sed -i.bak 's#substitute#replacement#g' "$WEB_CONF"

If your substitute and/or replacement has variables use " instead ' which will allow it to interpolate.

如果你的替换和/或替换有变量使用“代替”，这将允许它插入。

#1