得到错误sed: -e表达式#1,char 5:未知命令:' 0'

I am using the following code

我正在使用下面的代码。

      ff=`date +%h" "%Oe`
      pd=`date -d'yesterday' +%h" "%Oe`
      aa=`date -d'yesterday' +%d\/%m\/%Y`
      bb=`date +%d\/%m\/%Y`
      for j in `ls -lrt |egrep "$ff|$pd"|awk -F " " '{print $9}'`
      do
      sed -n "/${aa}/,/${bb}/p" ${j} 
      done

Logs from where I am fetching the data looks something like this

我从那里获取数据的日志看起来是这样的

      [2015-01-07 18:39:18,212] host123 WARN com.host123 .elf.UserQuest -  
      Quest/option {o.q.more.paper.osc#0} references unknown dependent   
      {t.what.form.file.more.action} in application {src-code}. Please            
      revise.

      [2015-01-07 18:39:18,212] host123 WARN com.host123 .elf.UserQuest -   
      Quest/option {o.q.more.paper.osc#1} references unknown dependent 
      {t.what.form.file.more.action} in application {src-code}. Please  
      revise.

      [2015-01-07 18:40:34,281] cessor32 ERROR com.host123 
      .email.DirectMailer -  Unable to connect to server {1.1.1.1}:
      javax.mail.MessagingException: Could not connect to SMTP host:  
      1.1.1.1, port: 25, response: 451
      at              
      com.sun.mail.smtp.SMTPTransport.openServer(SMTPTransport.java:996)
      at  
  com.sun.mail.smtp.SMTPTransport.protocolConnect(SMTPTransport.java:197)
   at javax.mail.Service.connect(Service.java:233)
   at javax.mail.Service.connect(Service.java:134)
   at               
   com.host123.email.DirectMailer.deliverMessage(DirectMailer.java:191)

I am getting the following error after executing the script

在执行脚本之后，我将得到以下错误

   sed: -e expression #1, char 5: unknown command: `0'

Please do suggest something.

请建议什么。

3 个解决方案

#1

The issue here is that you're using the / delimiter in your sed command, while at the same time using patterns that contain the same character. Try changing your sed command to this:

这里的问题是，您在sed命令中使用/分隔符，同时使用包含相同字符的模式。尝试将您的sed命令更改为以下命令:

sed -n "\#${aa}\#,\#${bb}\#p" "$j"

As NeronLeVelu has mentioned in the comments (thanks), it is necessary to escape the character with a backslash.

正如NeronLeVelu在评论中提到的(谢谢)，有必要用反斜杠来转义字符。

Alternatively, you could use awk to print your range of lines:

您也可以使用awk打印您的行范围:

awk -v s="$aa" -v e="$bb" '$0 ~ s, $0 ~ e' "$j"

#2

Tried making array out of ls -lrt |egrep "$ff|$pd"|awk -F " " '{print $9}' then loop through array?

尝试用ls -lrt |构建数组，然后循环遍历数组?

#3

The problem is that value of bb contains /s (Your sed command also using / as delimiter) . Try changing the line to:

问题是bb包含/s的值(您的sed命令也使用/作为分隔符)。试着把线改为:

sed -n "#${aa}#,#${bb}#p" ${j}

Another suggestion is to use the newer format of ff=$(date +%h" "%Oe)

另一个建议是使用ff=$(日期+%h”“%Oe)的新格式

#1