I have JQ function that send me file (I try to send path, but I need to send file. Now i need to receive in C# and convert to byte array.
我有发送文件的JQ函数(我尝试发送路径,但我需要发送文件。现在我需要在C#中接收并转换为字节数组。
If I have something like:
如果我有类似的东西:
$('#i_submit').click(function (event) {
$.ajax({
url: "Main/CP_Upload",
data: { "name": name,"type":type,"file":file }
});
});
(I check it is work, get file)
(我检查它是工作,获取文件)
Can i receive it like
我能收到它吗?
public void CP_Upload(string name,string type,File file)
(I get data, just I don't know is System.IO.File type that i need for definition of variable file...) Other question is can i type System.IO.File convert to byte array?
(我得到数据,只是我不知道是我需要的System.IO.File类型来定义变量文件...)其他问题是我可以输入System.IO.File转换为字节数组吗?
Thanx
1 个解决方案
#1
0
File.ReadAllBytes(string path)
will give you all the bytes from the file.
File.ReadAllBytes(字符串路径)将为您提供文件中的所有字节。
Alternatively you can give in FileInfo
parameter, and read each byte: (example)
或者你可以在FileInfo参数中给出,并读取每个字节:(示例)
var fi = new FileInfo(path);
using (FileStream fs = fi.OpenRead())
{
byte[] b = new byte[1024];
UTF8Encoding temp = new UTF8Encoding(true);
while (fs.Read(b,0,b.Length) > 0)
{
Console.WriteLine(temp.GetString(b));
}
}
#1
0
File.ReadAllBytes(string path)
will give you all the bytes from the file.
File.ReadAllBytes(字符串路径)将为您提供文件中的所有字节。
Alternatively you can give in FileInfo
parameter, and read each byte: (example)
或者你可以在FileInfo参数中给出,并读取每个字节:(示例)
var fi = new FileInfo(path);
using (FileStream fs = fi.OpenRead())
{
byte[] b = new byte[1024];
UTF8Encoding temp = new UTF8Encoding(true);
while (fs.Read(b,0,b.Length) > 0)
{
Console.WriteLine(temp.GetString(b));
}
}