python -m timeit: SyntaxError:从__future__导入必须在文件开始时发生。

时间:2021-01-22 19:57:20

I'd like to compare the execution time in different ways of forcing division to be floating point.

我想比较一下强制分割的不同方式的执行时间是浮点数。

While testing the following code with timeit in terminal,

在终端测试以下代码时,

from __future__ import division
a = 2/3

I encounter the error,

我遇到的错误,

$ python -m timeit '2*1.0/3'    # this works
10000000 loops, best of 3: 0.0578 usec per loop

$ python -m timeit -s 'from __future__ import division' '2/3'
Traceback (most recent call last):
  File "/usr/lib/python2.7/runpy.py", line 162, in _run_module_as_main
    "__main__", fname, loader, pkg_name)
  File "/usr/lib/python2.7/runpy.py", line 72, in _run_code
    exec code in run_globals
  File "/usr/lib/python2.7/timeit.py", line 330, in <module>
    sys.exit(main())
  File "/usr/lib/python2.7/timeit.py", line 294, in main
    t = Timer(stmt, setup, timer)
  File "/usr/lib/python2.7/timeit.py", line 136, in __init__
    code = compile(src, dummy_src_name, "exec")
  File "<timeit-src>", line 3
SyntaxError: from __future__ imports must occur at the beginning of the file

How do I measure the execution time for such a snippet code?

我如何度量这种代码片段的执行时间?

1 个解决方案

#1


1  

By enabling the behavior globally:

通过在全球范围内实现这种行为:

$ python -Q new -m timeit '2/3'
10000000 loops, best of 3: 0.0242 usec per loop

#1


1  

By enabling the behavior globally:

通过在全球范围内实现这种行为:

$ python -Q new -m timeit '2/3'
10000000 loops, best of 3: 0.0242 usec per loop