请问axis如何用wsdd部署（返回自定义类型）

一个web service 返回自定义类型  好象用jws 反序列化不行
用wsdd也部署不上，请高人指教！代码

服务端代码

/******************************************************************************
* File name:      *.java
* Create date:    2004-9-16
* Copyright:      Copyright (c) 2003 been protected by eazom
* @Author:        softteam
* @Version:       1.0
* To change the template for this generated file go to
* Window - Preferences - Java - Code Generation - Code and Comments
*
* Modify History
* Author           Date            Description
*/

/**
* @author Administrator
*
* To change the template for this generated type comment go to
* Window - Preferences - Java - Code Generation - Code and Comments
*/
public class WebObject1 {

/**
*
*/
public WebObject1() {
super();
// TODO Auto-generated constructor stub
}

public ReqMsg GetNameObject(ReqMsg r)
{
String newname="Bob"+r.get_Name();
int  newage =100+r.get_Age();
r.set_Name(newname);
r.set_Age(newage);
return r;
}

public static void main(String[] args) {
}
}
class ReqMsg
{
public ReqMsg(){}
String m_strName="";
int    m_nAge;

public String get_Name(){return m_strName;}
public void   set_Name(String strIn){m_strName=strIn;}

public int    get_Age(){return m_nAge;}
public void   set_Age(int nIn){m_nAge=nIn;}
}

//server-config.wsdd

<?xml version="1.0" encoding="UTF-8"?>
<deployment xmlns="http://xml.apache.org/axis/wsdd/" xmlns:java="http://xml.apache.org/axis/wsdd/providers/java">
<service name="WebObject1" provider="java:RPC">
  <parameter name="allowedMethods" value="*"/>
  <parameter name="className" value="WebObject1"/>
   <typeMapping deserializer="org.apache.axis.encoding.ser.BeanDeserializerFactory"
             encodingStyle="http://localhost"
             qname="ns3: ReqMsg"
             serializer="org.apache.axis.encoding.ser.BeanSerializerFactory"
             type="java:DefaultNamespace.ReqMsg"
             xmlns:ns2="http://localhost"/>
</service>
</deployment>

http://localhost/myapp/WebObject1.jws?wsdl
可以看到发布成功

客户端代码

import localhost.myapp.WebObject1_jws.*;
。。。。。。

try
{
WebObject1Service ws1 = new WebObject1ServiceLocator();
localhost.myapp.WebObject1_jws.WebObject1 w1  = ws1.getWebObject1();
DefaultNamespace.ReqMsg r1 =new DefaultNamespace.ReqMsg();
r1.set_Age(10);
r1.set_Name("coco");
DefaultNamespace.ReqMsg r2 = w1.getNameObject(r1);
System.out.println(r2.get_Name());
System.out.println(Integer.toString(r2.get_Age()));

}catch(Exception e)
{
e.printStackTrace();
}

结果

AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: org.xml.sax.SAXException: Deserializing parameter 'r':  could not find deserializer for type {http://DefaultNamespace}ReqMsg
faultActor:
faultNode:
faultDetail:
{http://xml.apache.org/axis/}stackTrace: AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: org.xml.sax.SAXException: Deserializing parameter &apos;r&apos;:  could not find deserializer for type {http://DefaultNamespace}ReqMsg
faultActor:
faultNode:
faultDetail:

org.xml.sax.SAXException: Deserializing parameter 'r':  could not find deserializer for type {http://DefaultNamespace}ReqMsg

请高手帮忙，谢谢！

7 个解决方案

#1

#2

class ReqMsg  implements Serializable{// you must add it.
public ReqMsg(){}
String m_strName="";
int    m_nAge;

public String get_Name(){return m_strName;}
public void   set_Name(String strIn){m_strName=strIn;}

public int    get_Age(){return m_nAge;}
public void   set_Age(int nIn){m_nAge=nIn;}
}

// I'd rather invoke the address from :
http://localhost/myapp/WebObject1

#3

远程方法调用的参数以及返回值对象都必须是可序列化的

http://www.javayou.com

#4

不懂，帮顶混分
好难啊

#5

错误在于qname="ns3: ReqMsg" 中，没有指出ns3的名字空间，使得axis序列化不知道如何匹配序列化类与名字空间的关系

#6

楼上所说正解...我原来也原到这个问题........就是不解解析自己定义类型.最后用jb来弄其所生成的wsdl就能让客户端能正确解析自定义类型...

#7

自定义的类型，还是借助IDE来开发比较好呢，
因为IDE要根据自定义类型，自动生成一些java的类。
自己写的话，如果不是对webservice开发很熟练，
是不知道要写些什么呢，还有命名的规则等等。

#1

#2

#3