I've done a fork and and then an exec but I don't know how to start it in the background.
我做了一个fork然后是一个exec，但我不知道如何在后台启动它。
Should I use an argument after the exec? If so, which is it?
我应该在执行后使用参数吗？如果是这样，这是什么？
1 个解决方案
#1
2
If you simply want to background a process use daemon().
如果您只是想要后台进程使用守护进程（）。
If you want to spawn off a process that then backgrounds itself 1st use fork() and inside this 1st child call fork() again letting the 2nd child call exec*() for the process to be backgrounded. Let the initial parent wait() for the 1st child.
如果你想生成一个进程，然后背景本身第一次使用fork（）并在第一个子调用fork（）中再次让第二个子进程调用exec *（）来进行后台处理。让第一个孩子的初始父等待（）。
As the parent of the second child (the process fork()ed 1st) dies, the exec*()ed process will be reaped by init.
当第二个子节点的父节点（进程fork（）ed 1st）消失时，exec *（）ed进程将由init获取。
Note: The pattern above is sometimes referred to as "double-forking". See also here: Why fork() twice (and links from there)
注意：上面的模式有时被称为“双重分叉”。另见：这里为什么fork（）两次（和那里的链接）
Another interesting set of answers on this is here: Linux: Difference between forking twice and daemon(ise)
另一个有趣的答案就在这里：Linux：分叉两次和守护进程（ise）之间的区别
#1
2
If you simply want to background a process use daemon().
如果您只是想要后台进程使用守护进程（）。
If you want to spawn off a process that then backgrounds itself 1st use fork() and inside this 1st child call fork() again letting the 2nd child call exec*() for the process to be backgrounded. Let the initial parent wait() for the 1st child.
如果你想生成一个进程，然后背景本身第一次使用fork（）并在第一个子调用fork（）中再次让第二个子进程调用exec *（）来进行后台处理。让第一个孩子的初始父等待（）。
As the parent of the second child (the process fork()ed 1st) dies, the exec*()ed process will be reaped by init.
当第二个子节点的父节点（进程fork（）ed 1st）消失时，exec *（）ed进程将由init获取。
Note: The pattern above is sometimes referred to as "double-forking". See also here: Why fork() twice (and links from there)
注意：上面的模式有时被称为“双重分叉”。另见：这里为什么fork（）两次（和那里的链接）
Another interesting set of answers on this is here: Linux: Difference between forking twice and daemon(ise)
另一个有趣的答案就在这里：Linux：分叉两次和守护进程（ise）之间的区别