Django:如何创建到视图的通用URL路由?

时间:2021-11-27 19:16:21

I have a pretty standard django app, and am wondering how to set the url routing so that I don't have to explicitly map each url to a view.

我有一个非常标准的django应用程序,我想知道如何设置URL路由,以便我不必显式地将每个URL映射到视图。

For example, let's say that I have the following views: Project, Links, Profile, Contact. I'd rather not have my urlpatterns look like this:

例如,假设我有以下视图:项目,链接,配置文件,联系人。我宁愿没有我的urlpatterns看起来像这样:

(r'^Project/$', 'mysite.app.views.project'),
(r'^Links/$', 'mysite.app.views.links'),
(r'^Profile/$', 'mysite.app.views.profile'),
(r'^Contact/$', 'mysite.app.views.contact'),

And so on. In Pylons, it would be as simple as:

等等。在Pylons中,它将如此简单:

map.connect(':controller/:action/:id')

And it would automatically grab the right controller and function. Is there something similar in Django?

它会自动抓取正确的控制器和功能。 Django有类似的东西吗?

3 个解决方案

#1


5  

mods = ('Project','Links','Profile','Contact')

urlpatterns = patterns('',
   *(('^%s/$'%n, 'mysite.app.views.%s'%n.lower()) for n in mods)
)

#2


5  

Unless you have a really huge number of views, writing them down explicitly is not too bad, from a style perspective.

除非你有非常多的观点,从风格的角度来看,明确地写下它们并不算太糟糕。

You can shorten your example, though, by using the prefix argument of the patterns function:

但是,您可以通过使用patterns函数的prefix参数来缩短示例:

urlpatterns = patterns('mysite.app.views',
    (r'^Project/$', 'project'),
    (r'^Links/$', 'links'),
    (r'^Profile/$', 'profile'),
    (r'^Contact/$', 'contact'),
)

#3


5  

You might be able to use a special view function along these lines:

您可以沿着这些方向使用特殊视图功能:

def router(request, function, module):
    m =__import__(module, globals(), locals(), [function.lower()])
    try:
        return m.__dict__[function.lower()](request)
    except KeyError:
        raise Http404()

and then a urlconf like this:

然后像这样的urlconf:

(r'^(?P<function>.+)/$', router, {"module": 'mysite.app.views'}),

This code is untested but the general idea should work, even though you should remember:

这段代码未经测试,但总体思路应该有效,即使您应该记住:

Explicit is better than implicit.

显式优于隐式。

#1


5  

mods = ('Project','Links','Profile','Contact')

urlpatterns = patterns('',
   *(('^%s/$'%n, 'mysite.app.views.%s'%n.lower()) for n in mods)
)

#2


5  

Unless you have a really huge number of views, writing them down explicitly is not too bad, from a style perspective.

除非你有非常多的观点,从风格的角度来看,明确地写下它们并不算太糟糕。

You can shorten your example, though, by using the prefix argument of the patterns function:

但是,您可以通过使用patterns函数的prefix参数来缩短示例:

urlpatterns = patterns('mysite.app.views',
    (r'^Project/$', 'project'),
    (r'^Links/$', 'links'),
    (r'^Profile/$', 'profile'),
    (r'^Contact/$', 'contact'),
)

#3


5  

You might be able to use a special view function along these lines:

您可以沿着这些方向使用特殊视图功能:

def router(request, function, module):
    m =__import__(module, globals(), locals(), [function.lower()])
    try:
        return m.__dict__[function.lower()](request)
    except KeyError:
        raise Http404()

and then a urlconf like this:

然后像这样的urlconf:

(r'^(?P<function>.+)/$', router, {"module": 'mysite.app.views'}),

This code is untested but the general idea should work, even though you should remember:

这段代码未经测试,但总体思路应该有效,即使您应该记住:

Explicit is better than implicit.

显式优于隐式。