为什么Celery在Python shell中工作，而不是在我的Django视图中？ （进口问题）

I installed Celery (latest stable version.) I have a directory called /home/myuser/fable/jobs. Inside this directory, I have a file called tasks.py:

我安装了Celery（最新的稳定版本。）我有一个名为/ home / myuser / fable / jobs的目录。在这个目录中，我有一个名为tasks.py的文件：

from celery.decorators import task
from celery.task import Task

class Submitter(Task):
    def run(self, post, **kwargs):
        return "Yes, it works!!!!!!"

Inside this directory, I also have a file called celeryconfig.py:

在这个目录中，我还有一个名为celeryconfig.py的文件：

BROKER_HOST = "localhost"
BROKER_PORT = 5672
BROKER_USER = "abc"
BROKER_PASSWORD = "xyz"
BROKER_VHOST = "fablemq"

CELERY_RESULT_BACKEND = "amqp"
CELERY_IMPORTS = ("tasks", )

In my /etc/profile, I have these set as my PYTHONPATH:

在我的/ etc / profile中，我将这些设置为我的PYTHONPATH：

• PYTHONPATH=/home/myuser/fable:/home/myuser/fable/jobs
• PYTHONPATH = /家/ myuser的/寓言：/首页/ myuser的/寓言/工作

So I run my Celery worker using the console ($ celeryd --loglevel=INFO), and I try it out. I open the Python console and import the tasks. Then, I run the Submitter.

所以我使用控制台运行我的Celery工作者（$ celeryd --loglevel = INFO），然后我试试看。我打开Python控制台并导入任务。然后，我运行提交者。

>>> import fable.jobs.tasks as tasks
>>> s = tasks.Submitter()
>>> s.delay("abc")
<AsyncResult: d70d9732-fb07-4cca-82be-d7912124a987>

Everything works, as you can see in my console

一切正常，正如您在我的控制台中看到的那样

[2011-01-09 17:30:05,766: INFO/MainProcess] Task tasks.Submitter[d70d9732-fb07-4cca-82be-d7912124a987] succeeded in 0.0398268699646s:

But when I go into my Django's views.py and run the exact 3 lines of code as above, I get this:

但是当我进入我的Django的views.py并运行上面的3行代码时，我得到了这个：

[2011-01-09 17:25:20,298: ERROR/MainProcess] Unknown task ignored: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported.": {'retries': 0, 'task': 'fable.jobs.tasks.Submitter', 'args': ('abc',), 'expires': None, 'eta': None, 'kwargs': {}, 'id': 'eb5c65b4-f352-45c6-96f1-05d3a5329d53'}
Traceback (most recent call last):
  File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/listener.py", line 321, in receive_message
    eventer=self.event_dispatcher)
  File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 299, in from_message
    eta=eta, expires=expires)
  File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 243, in __init__
    self.task = tasks[self.task_name]
  File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/registry.py", line 63, in __getitem__
    raise self.NotRegistered(str(exc))
NotRegistered: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported."

It's weird, because the celeryd client does show that it's registered, when I launch it.

这很奇怪，因为当我启动它时，celeryd客户端确实显示它已注册。

[2011-01-09 17:38:27,446: WARNING/MainProcess]  
Configuration ->
    . broker -> amqp://GOGOme@localhost:5672/fablemq
    . queues ->
        . celery -> exchange:celery (direct) binding:celery
    . concurrency -> 1
    . loader -> celery.loaders.default.Loader
    . logfile -> [stderr]@INFO
    . events -> OFF
    . beat -> OFF
    . tasks ->
        . tasks.Decayer
        . tasks.Submitter

Can someone help?

有人可以帮忙吗？

3 个解决方案

#1

I believe your tasks.py file needs to be in a django app (that's registered in settings.py) in order to be imported. Alternatively, you might try importing the tasks from an __init__.py file in your main project or one of the apps.

我相信你的tasks.py文件需要在django应用程序（在settings.py中注册）才能导入。或者，您可以尝试从主项目或其中一个应用程序中的__init__.py文件导入任务。

Also try starting celeryd from manage.py:

还可以尝试从manage.py启动celeryd：

$ python manage.py celeryd -E -B -lDEBUG

(-E and -B may or may not be necessary, but that's what I use).

（-E和-B可能是也可能不是必需的，但这就是我使用的）。

#2

This is what I did which finally worked

这就是我最终的工作

in Settings.py I added

在Settings.py中我添加了

CELERY_IMPORTS = ("myapp.jobs", )

under myapp folder I created a file called jobs.py

在myapp文件夹下，我创建了一个名为jobs.py的文件

from celery.decorators import task

@task(name="jobs.add")
def add(x, y):
    return x * y

Then ran from commandline: python manage.py celeryd -l info

然后从命令行运行：python manage.py celeryd -l info

in another shell i ran python manage.py shell, then

在另一个shell中我运行了python manage.py shell，然后

>>> from myapp.jobs import add
>>> result = add.delay(4, 4)
>>> result.result

and the i get:

而我得到：

16

16

The important point is that you have to rerun both command shells when you add a new function. You have to register the name both on the client and and on the server.

重要的是，在添加新函数时必须重新运行两个命令shell。您必须在客户端和服务器上注册该名称。

:-)

:-)

#3

See Automatic Naming and Relative Imports, in the docs:

请参阅文档中的自动命名和相对导入：

http://celeryq.org/docs/userguide/tasks.html#automatic-naming-and-relative-imports

http://celeryq.org/docs/userguide/tasks.html#automatic-naming-and-relative-imports

The tasks name is "tasks.Submitter" (as listed in the celeryd output), but you import the task as "fable.jobs.tasks.Submitter"

任务名称是“tasks.Submitter”（如celeryd输出中所列），但您将任务导入为“fable.jobs.tasks.Submitter”

I guess the best solution here is if the worker also sees it as "fable.jobs.tasks.Submitter", it makes more sense from an app perspective.

我想这里最好的解决方案是如果工作者也将其视为“fable.jobs.tasks.Submitter”，从应用程序的角度来看它更有意义。

CELERY_IMPORTS = ("fable.jobs.tasks", )