I have a fixed date from MySql
我有一个MySql的固定日期
startDate = 07/03/2011
I wanted to add 60 days on top this date to have an endDate.
我想在这个日期添加60天以获得endDate。
$startDate = $result['startDate'];
$endDate = ??? + strtotime("+60 days");
echo $endDate;
From my research, I know it has something do with strtotime, but all the sites I come across with based the start date from current workstation's time. My date is already fixed and entered prior to running and getting the endDate.
根据我的研究,我知道它与strtotime有关,但我遇到的所有网站都基于当前工作站的开始日期。我的日期已经修复并在运行和获取endDate之前输入。
Help? Thanks in advance!
救命?提前致谢!
4 个解决方案
#1
8
In addition to PHP solutions others are providing, you can create the endDate
right inside of MySQL and save yourself some of the trouble:
除了其他人提供的PHP解决方案之外,您还可以在MySQL内部创建endDate并省去一些麻烦:
SELECT startDate, DATE_ADD(startDate, INTERVAL 60 DAY) AS endDate FROM table;
-- Or by months (not exactly the same thing)
SELECT startDate, DATE_ADD(startDate, INTERVAL 2 MONTH) AS endDate FROM table;
Relevant documentation here...
这里的相关文件......
#2
5
You could reformat the results of strtotime()
你可以重新格式化strtotime()的结果
$startDate = $result['startDate']; // 07/03/2011
$endDate = date("m/d/Y", strtotime("$startDate +60 days"));
#3
2
$startDate = "07/03/2011";
$endDate = strtotime("+60 days",time($startDate));
$formatted = date('m/d/Y',$endDate);
echo $endDate . "<br/>" . $formatted;
#4
1
86400 seconds in a day, times number of days.. and add it to current time.
一天86400秒,乘以天数..并将其添加到当前时间。
$nextMonth = time()+86400*60;
echo date("Y-m-d H:i:s", $nextMonth);
#1
8
In addition to PHP solutions others are providing, you can create the endDate
right inside of MySQL and save yourself some of the trouble:
除了其他人提供的PHP解决方案之外,您还可以在MySQL内部创建endDate并省去一些麻烦:
SELECT startDate, DATE_ADD(startDate, INTERVAL 60 DAY) AS endDate FROM table;
-- Or by months (not exactly the same thing)
SELECT startDate, DATE_ADD(startDate, INTERVAL 2 MONTH) AS endDate FROM table;
Relevant documentation here...
这里的相关文件......
#2
5
You could reformat the results of strtotime()
你可以重新格式化strtotime()的结果
$startDate = $result['startDate']; // 07/03/2011
$endDate = date("m/d/Y", strtotime("$startDate +60 days"));
#3
2
$startDate = "07/03/2011";
$endDate = strtotime("+60 days",time($startDate));
$formatted = date('m/d/Y',$endDate);
echo $endDate . "<br/>" . $formatted;
#4
1
86400 seconds in a day, times number of days.. and add it to current time.
一天86400秒,乘以天数..并将其添加到当前时间。
$nextMonth = time()+86400*60;
echo date("Y-m-d H:i:s", $nextMonth);