C++14 supports generic lambdas. However, the following code is rejected by clang 3.4.
C ++ 14支持通用lambdas。但是,clang 3.4拒绝以下代码。
#include <utility>
void f(int);
void f(int&);
int main()
{
[](auto&& v) { f(std::forward<auto>(v)); }(8); // error
}
How to perfectly forward auto&& in a generic lambda?
如何在一般的lambda中完美地转发auto &&?
1 个解决方案
#1
26
auto is not a type so I’m not surprised this doesn’t work. But can’t you use decltype?
汽车不是一种类型所以我并不感到惊讶,这不起作用。但是你不能使用decltype吗?
[](auto&& v) { f(std::forward<decltype(v)>(v)); }(8);
Scott Meyers has more details.
Scott Meyers有更多细节。
#1
26
auto is not a type so I’m not surprised this doesn’t work. But can’t you use decltype?
汽车不是一种类型所以我并不感到惊讶,这不起作用。但是你不能使用decltype吗?
[](auto&& v) { f(std::forward<decltype(v)>(v)); }(8);
Scott Meyers has more details.
Scott Meyers有更多细节。