Objective: Change the Column Names of all the Data Frames in the Global Environment from the following list
目的:从以下列表中更改全局环境中所有数据帧的列名。
colnames of the ones in global environment
全局环境下的名称
So.
所以。
0) The Column names are:
0)列名为:
colnames = c("USAF","WBAN","YR--MODAHRMN")
1) I have the following data.frames: df1, df2.
1)我有以下数据。帧:df1, df2。
2) I put them in a list:
我把它们列在一张清单上:
dfList <- list(df1,df2)
3) Loop through the list:
3)循环浏览列表:
for (df in dfList){
colnames(df)=colnames
}
But this creates a new df with the column names that I need, it doesn't change the original column names in df1, df2. Why? Could lapply be a solution? Thanks
但这会创建一个新的df,包含我需要的列名,它不会改变df1, df2中的原始列名。为什么?lapply是一个解决方案吗?谢谢
Can something like:
可以这样:
lapply(dfList, function(x) {colnames(dfList)=colnames})
work?
工作吗?
3 个解决方案
#1
16
With lapply you can do it as follows.
用lapply,你可以这样做。
Create sample data:
创建示例数据:
df1 <- data.frame(A = 1, B = 2, C = 3)
df2 <- data.frame(X = 1, Y = 2, Z = 3)
dfList <- list(df1,df2)
colnames <- c("USAF","WBAN","YR--MODAHRMN")
Then, lapply over the list using setNames
and supply the vector of new column names as second argument to setNames
:
然后,使用setNames在列表上进行lapply,并将新列名的vector作为第二个参数用于setNames:
lapply(dfList, setNames, colnames)
#[[1]]
# USAF WBAN YR--MODAHRMN
#1 1 2 3
#
#[[2]]
# USAF WBAN YR--MODAHRMN
#1 1 2 3
Edit
编辑
If you want to assign the data.frames back to the global environment, you can modify the code like this:
如果您想将data.frame分配回全局环境,可以这样修改代码:
dfList <- list(df1 = df1, df2 = df2)
list2env(lapply(dfList, setNames, colnames), .GlobalEnv)
#2
4
Just change your for-loop into an index for-loop like this:
只需将for-loop改为index for-loop,如下所示:
Data
数据
df1 <- data.frame(a=runif(5), b=runif(5), c=runif(5))
df2 <- data.frame(a=runif(5), b=runif(5), c=runif(5))
dflist <- list(df1,df2)
colnames = c("USAF","WBAN","YR--MODAHRMN")
Solution
解决方案
for (i in seq_along(dflist)){
colnames(dflist[[i]]) <- colnames
}
Output
输出
> dflist
[[1]]
USAF WBAN YR--MODAHRMN
1 0.8794153 0.7025747 0.2136040
2 0.8805788 0.8253530 0.5467952
3 0.1719539 0.5303908 0.5965716
4 0.9682567 0.5137464 0.4038919
5 0.3172674 0.1403439 0.1539121
[[2]]
USAF WBAN YR--MODAHRMN
1 0.20558383 0.62651334 0.4365940
2 0.43330717 0.85807280 0.2509677
3 0.32614750 0.70782919 0.6319263
4 0.02957656 0.46523151 0.2087086
5 0.58757198 0.09633181 0.6941896
By using for (df in dfList)
you are essentially creating a new df each time and change the column names to that leaving the original list (dfList
) untouched.
通过使用for (dfList中的df),您实际上每次都创建一个新的df,并将列名更改为保持原始列表(dfList)不变。
#3
0
If you want the for
loop to work, you should not pass the whole data.frame as the argument.
如果希望for循环工作,则不应该将整个data.frame作为参数传递。
for (df in 1:length(dfList))
colnames(dfList[[df]]) <- colnames
#1
16
With lapply you can do it as follows.
用lapply,你可以这样做。
Create sample data:
创建示例数据:
df1 <- data.frame(A = 1, B = 2, C = 3)
df2 <- data.frame(X = 1, Y = 2, Z = 3)
dfList <- list(df1,df2)
colnames <- c("USAF","WBAN","YR--MODAHRMN")
Then, lapply over the list using setNames
and supply the vector of new column names as second argument to setNames
:
然后,使用setNames在列表上进行lapply,并将新列名的vector作为第二个参数用于setNames:
lapply(dfList, setNames, colnames)
#[[1]]
# USAF WBAN YR--MODAHRMN
#1 1 2 3
#
#[[2]]
# USAF WBAN YR--MODAHRMN
#1 1 2 3
Edit
编辑
If you want to assign the data.frames back to the global environment, you can modify the code like this:
如果您想将data.frame分配回全局环境,可以这样修改代码:
dfList <- list(df1 = df1, df2 = df2)
list2env(lapply(dfList, setNames, colnames), .GlobalEnv)
#2
4
Just change your for-loop into an index for-loop like this:
只需将for-loop改为index for-loop,如下所示:
Data
数据
df1 <- data.frame(a=runif(5), b=runif(5), c=runif(5))
df2 <- data.frame(a=runif(5), b=runif(5), c=runif(5))
dflist <- list(df1,df2)
colnames = c("USAF","WBAN","YR--MODAHRMN")
Solution
解决方案
for (i in seq_along(dflist)){
colnames(dflist[[i]]) <- colnames
}
Output
输出
> dflist
[[1]]
USAF WBAN YR--MODAHRMN
1 0.8794153 0.7025747 0.2136040
2 0.8805788 0.8253530 0.5467952
3 0.1719539 0.5303908 0.5965716
4 0.9682567 0.5137464 0.4038919
5 0.3172674 0.1403439 0.1539121
[[2]]
USAF WBAN YR--MODAHRMN
1 0.20558383 0.62651334 0.4365940
2 0.43330717 0.85807280 0.2509677
3 0.32614750 0.70782919 0.6319263
4 0.02957656 0.46523151 0.2087086
5 0.58757198 0.09633181 0.6941896
By using for (df in dfList)
you are essentially creating a new df each time and change the column names to that leaving the original list (dfList
) untouched.
通过使用for (dfList中的df),您实际上每次都创建一个新的df,并将列名更改为保持原始列表(dfList)不变。
#3
0
If you want the for
loop to work, you should not pass the whole data.frame as the argument.
如果希望for循环工作,则不应该将整个data.frame作为参数传递。
for (df in 1:length(dfList))
colnames(dfList[[df]]) <- colnames