I am using Django 1.7, Pyton 3.4 and PostgreSQL 9.1. I have problem with filtering users using field from UserProfile. Here is my UserProfile in models.py
我正在使用Django 1.7,Pyton 3.4和PostgreSQL 9.1。我在使用UserProfile中的字段过滤用户时遇到问题。这是models.py中的UserProfile
class UserProfile(models.Model):
user = models.OneToOneField(User)
is_agency = models.BooleanField(blank=False, default=False)
customer_linked = models.ForeignKey(Customer, null=True, blank=True)
I can add now new user, but I would like to display list of users that in profile are 'is_agency' checked and Customer's name that is in ForeignKey. I am struggling with my view:
我现在可以添加新用户,但我想显示在配置文件中选中'is_agency'的用户列表以及在ForeignKey中的客户名称。我正在努力解决我的看法:
def agency_list(request):
users = UserProfile.objects.filter(is_agency = True)
return render_to_response('agency/list.html', {'users': users}, context_instance=RequestContext(request))
and my template is:
我的模板是:
{% for user in users %}
<tr>
<td>{{ user.username }}</td>
<td> --here Customer's name--</td>
</tr>
{% endfor %}
Any ideas how can I fix my view.py and list.html?
任何想法如何修复我的view.py和list.html?
Thanks
谢谢
1 个解决方案
#1
1
Leave the view as is and change the template to:
保持视图不变并将模板更改为:
{% for profile in users %}
<tr>
<td>{{ profile.user.username }}</td>
<td>{{ profile.customer_linked.name }}</td>
</tr>
{% endfor %}
Side note: to increase speed and reduce the number of DB hits use the select_related()
method:
附注:要提高速度并减少数据库命中数,请使用select_related()方法:
users = UserProfile.objects.select_related().filter(is_agency=True)
#1
1
Leave the view as is and change the template to:
保持视图不变并将模板更改为:
{% for profile in users %}
<tr>
<td>{{ profile.user.username }}</td>
<td>{{ profile.customer_linked.name }}</td>
</tr>
{% endfor %}
Side note: to increase speed and reduce the number of DB hits use the select_related()
method:
附注:要提高速度并减少数据库命中数,请使用select_related()方法:
users = UserProfile.objects.select_related().filter(is_agency=True)