A. Comparing Two Long Integers
题目连接：
http://www.codeforces.com/contest/616/problem/A
Description
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Sample Input
9
10
Sample Output
<
Hint
题意
给你两个带前导0的高精度数字，然后让你比大小。
题解：
模拟一下就好了，首先看数位，然后再看每一位的数字就行了
代码
#include<bits/stdc++.h>
using namespace std;
string a,b;
int main()
{
cin>>a>>b;
int len1 = a.size(),len2 = b.size();
int la = 0,lb = 0;
while(a[la]=='0'&&la<len1)la++;
while(b[lb]=='0'&&lb<len2)lb++;
if(len1-la>len2-lb)return puts(">");
if(len1-la<len2-lb)return puts("<");
for(int i=la;i<len1;i++)
{
if(a[i]>b[i-la+lb])return puts(">");
if(a[i]<b[i-la+lb])return puts("<");
}
return puts("=");
}