Python 2: AttributeError: 'list'对象没有'strip'属性

I have a small problem with list. So i have a list called l:

我对列表有个小问题。我有一个列表叫l:

l = ['Facebook;Google+;MySpace', 'Apple;Android']

And as you can see I have only 2 strings in my list. I want to separate my list l by ';' and put my new 5 strings into a new list called l1.

可以看到，我的列表中只有两个字符串。我想把我的列表l和';'分开，把我新的5个字符串放到一个叫做l1的新列表中。

How can I do that?

我该怎么做呢?

And also I have tried to do this like this:

我也试过这样做:

l1 = l.strip().split(';')

But Python give me an error:

但是Python给了我一个错误:

AttributeError: 'list' object has no attribute 'strip'

So if 'list' object has no attribute 'strip' or 'split', how can I split a list?

所以如果'list'对象没有'strip'或'split'属性，我如何分割列表?

Thanks

谢谢

7 个解决方案

#1

strip() is a method for strings, you are calling it on a list, hence the error.

strip()是一个字符串方法，您正在一个列表上调用它，因此出现了错误。

>>> 'strip' in dir(str)
True
>>> 'strip' in dir(list)
False

To do what you want, just do

做你想做的，就去做

>>> l = ['Facebook;Google+;MySpace', 'Apple;Android']
>>> l1 = [elem.strip().split(';') for elem in l]
>>> print l1
[['Facebook', 'Google+', 'MySpace'], ['Apple', 'Android']]

Since, you want the elements to be in a single list (and not a list of lists), you have two options.

因为，您希望元素位于一个列表(而不是列表列表)中，所以您有两个选项。

Create an empty list and append elements to it.
创建一个空列表并向其添加元素。
Flatten the list.
压平。

To do the first, follow the code:

要执行第一个步骤，请遵循以下代码:

>>> l1 = []
>>> for elem in l:
        l1.extend(elem.strip().split(';'))  
>>> l1
['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']

To do the second, use itertools.chain

要执行第二个操作，请使用itertools.chain

>>> l1 = [elem.strip().split(';') for elem in l]
>>> print l1
[['Facebook', 'Google+', 'MySpace'], ['Apple', 'Android']]
>>> from itertools import chain
>>> list(chain(*l1))
['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']

#2

This should be what you want:

这应该是你想要的:

[x for y in l for x in y.split(";")]

output:

输出:

['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']

#3

Hope this helps :)

希望这有助于:)

>>> x = [i.split(";") for i in l]
>>> x
[['Facebook', 'Google+', 'MySpace'], ['Apple', 'Android']]
>>> z = [j for i in x for j in i]
>>> z
['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']
>>>

#4

What you want to do is -

你想做的是-

strtemp = ";".join(l)

The first line adds a ; to the end of MySpace so that while splitting, it does not give out MySpaceApple This will join l into one string and then you can just-

第一行加a;在MySpace结束时，它不会释放MySpaceApple这个会把l连接到一个字符串然后你可以

l1 = strtemp.split(";")

This works because strtemp is a string which has .split()

这样做是因为strtemp是一个具有.split()的字符串

#5

One possible solution I have tried right now is: (Make sure do it in general way using for, while with index)

我现在尝试的一个可能的解决方案是:(在使用索引时，一定要用一般的方法)

>>> l=['Facebook;Google+;MySpace', 'Apple;Android']
>>> new1 = l[0].split(';')
>>> new1
['Facebook', 'Google+', 'MySpace']
>>> new2= l[1].split(';')`enter code here`
>>> new2
['Apple', 'Android']
>>> totalnew = new1 + new2
>>> totalnew
['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']

#6

You split the string entry of the list. l[0].strip()

分割列表的字符串条目。l[0].strip()

#7

Split the strings and then use chain.from_iterable to combine them into a single list

分割字符串，然后使用chain.from_iterable将它们合并到一个列表中

>>> import itertools
>>> l = ['Facebook;Google+;MySpace', 'Apple;Android']
>>> l1 = [ x for x in itertools.chain.from_iterable( x.split(';') for x in l ) ]
>>> l1
['Facebook', 'Google+', 'MySpace', 'Apple', 'Android']

#1