I would like to remove an empty String from List of Strings.
我想从字符串列表中删除一个空字符串。
Here is what I tried, using the stream API:
以下是我尝试使用流API的方法:
list.stream().filter(item-> !item.isEmpty()).collect(Collectors.toList());
and the empty string is still present in the list. What am I missing ?
并且列表中仍然存在空字符串。我错过了什么?
9 个解决方案
#1
14
filter()
keeps the elements that match the predicate. Soyou need the inverse predicate:
filter()保留与谓词匹配的元素。 Soyou需要逆谓词:
list.stream().filter(item-> !item.isEmpty()).collect(Collectors.toList());
This will also not modify the original list. It will create a filtered copy of the original list. So you need
这也不会修改原始列表。它将创建原始列表的过滤副本。所以你需要
list = list.stream().filter(item-> !item.isEmpty()).collect(Collectors.toList());
If you want to modify the original list, you should use
如果要修改原始列表,则应使用
list.removeIf(item -> item.isEmpty());
or simply
或简单地说
list.removeIf(String::isEmpty);
#2
3
I suspect you are not keeping the result. The result is returned, the original list is not altered as this is functional programming style.
我怀疑你没有保留结果。返回结果,原始列表不会改变,因为这是函数式编程风格。
list = list.stream().filter(item-> !item.trim().isEmpty()).collect(Collectors.toList());
#3
2
Maybe the string contains whitespaces? Replace item -> item.isEmpty()
with item -> !item.trim().isEmpty()
也许字符串包含空格?用item - >!item.trim()替换item - > item.isEmpty()。isEmpty()
#4
1
you are collecting the empty elements :)
你正在收集空元素:)
you want the not empty so invert the predicate
你想要不空,所以反转谓词
List<String> xxx = list.stream().filter(item -> !item.isEmpty()).collect(Collectors.toList());
additionally, the stream is not modifying the original list, so Collect(Collectrors.toList())
is returning the result of the predicate :)
另外,流不修改原始列表,因此Collect(Collectrors.toList())返回谓词的结果:)
#5
0
You are removing non-empty strings (check your filter condition). Try:
您正在删除非空字符串(检查您的过滤条件)。尝试:
list.stream().filter(item -> !item.isEmpty()).collect(Collectors.toList());
Otherwise, you may need to check that you're removing blanks as well:
否则,您可能需要检查是否还要删除空白:
list.stream().filter(item -> !item.trim().isEmpty()).collect(Collectors.toList());
#6
0
You are not removing empty Strings from the list, you were retrieving them. Your filter condition is wrong.
您没有从列表中删除空字符串,而是检索它们。您的过滤条件有误。
Try like this:
试试这样:
List<String> collect = list.stream().filter(item -> !item.trim().isEmpty()).collect(Collectors.toList());
#7
0
you can follow below example, it may help you
你可以按照下面的例子,它可以帮助你
String[] firstArray = {"test1", "", "test2", "test4", "", null};
firstArray = Arrays.stream(firstArray).filter(s -> (s != null && s.length() > 0)).toArray(String[]::new);
#8
0
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-lang3</artifactId>
<version>3.5-SNAPSHOT</version>
</dependency>
import org.apache.commons.lang3.StringUtils;
//Java8 new api
strings.removeIf(StringUtils::isBlank);
//stream strings=strings.stream().filter(StringUtils::isNotBlank).collect(Collectors.toList());
#9
0
Might be your List contains null. So first filter with null check then again filter on empty
你的List可能包含null。所以先用null检查过滤然后再过滤空
list.stream().filter(item -> null != item).filter(item -> !item.isEmpty()).collect(Collectors.toList());
If you have apache commons lang lib use Apache StringUtils isNotBlank
如果你有apache commons lang lib,请使用Apache StringUtils isNotBlank
list.stream().filter(item -> StrinUtils.isNotBlank(item)).collect(Collectors.toList());
#1
14
filter()
keeps the elements that match the predicate. Soyou need the inverse predicate:
filter()保留与谓词匹配的元素。 Soyou需要逆谓词:
list.stream().filter(item-> !item.isEmpty()).collect(Collectors.toList());
This will also not modify the original list. It will create a filtered copy of the original list. So you need
这也不会修改原始列表。它将创建原始列表的过滤副本。所以你需要
list = list.stream().filter(item-> !item.isEmpty()).collect(Collectors.toList());
If you want to modify the original list, you should use
如果要修改原始列表,则应使用
list.removeIf(item -> item.isEmpty());
or simply
或简单地说
list.removeIf(String::isEmpty);
#2
3
I suspect you are not keeping the result. The result is returned, the original list is not altered as this is functional programming style.
我怀疑你没有保留结果。返回结果,原始列表不会改变,因为这是函数式编程风格。
list = list.stream().filter(item-> !item.trim().isEmpty()).collect(Collectors.toList());
#3
2
Maybe the string contains whitespaces? Replace item -> item.isEmpty()
with item -> !item.trim().isEmpty()
也许字符串包含空格?用item - >!item.trim()替换item - > item.isEmpty()。isEmpty()
#4
1
you are collecting the empty elements :)
你正在收集空元素:)
you want the not empty so invert the predicate
你想要不空,所以反转谓词
List<String> xxx = list.stream().filter(item -> !item.isEmpty()).collect(Collectors.toList());
additionally, the stream is not modifying the original list, so Collect(Collectrors.toList())
is returning the result of the predicate :)
另外,流不修改原始列表,因此Collect(Collectrors.toList())返回谓词的结果:)
#5
0
You are removing non-empty strings (check your filter condition). Try:
您正在删除非空字符串(检查您的过滤条件)。尝试:
list.stream().filter(item -> !item.isEmpty()).collect(Collectors.toList());
Otherwise, you may need to check that you're removing blanks as well:
否则,您可能需要检查是否还要删除空白:
list.stream().filter(item -> !item.trim().isEmpty()).collect(Collectors.toList());
#6
0
You are not removing empty Strings from the list, you were retrieving them. Your filter condition is wrong.
您没有从列表中删除空字符串,而是检索它们。您的过滤条件有误。
Try like this:
试试这样:
List<String> collect = list.stream().filter(item -> !item.trim().isEmpty()).collect(Collectors.toList());
#7
0
you can follow below example, it may help you
你可以按照下面的例子,它可以帮助你
String[] firstArray = {"test1", "", "test2", "test4", "", null};
firstArray = Arrays.stream(firstArray).filter(s -> (s != null && s.length() > 0)).toArray(String[]::new);
#8
0
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-lang3</artifactId>
<version>3.5-SNAPSHOT</version>
</dependency>
import org.apache.commons.lang3.StringUtils;
//Java8 new api
strings.removeIf(StringUtils::isBlank);
//stream strings=strings.stream().filter(StringUtils::isNotBlank).collect(Collectors.toList());
#9
0
Might be your List contains null. So first filter with null check then again filter on empty
你的List可能包含null。所以先用null检查过滤然后再过滤空
list.stream().filter(item -> null != item).filter(item -> !item.isEmpty()).collect(Collectors.toList());
If you have apache commons lang lib use Apache StringUtils isNotBlank
如果你有apache commons lang lib,请使用Apache StringUtils isNotBlank
list.stream().filter(item -> StrinUtils.isNotBlank(item)).collect(Collectors.toList());