python：从列表创建元组列表[重复]

I have two lists:

我有两个清单:

x = ['1', '2', '3']
y = ['a', 'b', 'c']

and I need to create a list of tuples from these lists, as follows:

我需要从这些列表中创建一个元组列表,如下所示:

z = [('1','a'), ('2','b'), ('3','c')]

I tried doing it like this:

我尝试这样做:

z = [ (a,b) for a in x for b in y ]

but resulted in:

但结果是:

[('1', '1'), ('1', '2'), ('1', '3'), ('2', '1'), ('2', '2'), ('2', '3'), ('3', '1'), ('3', '2'), ('3', '3')]

i.e. a list of tuples of every element in x with every element in y... what is the right approach to do what I wanted to do? thank you...

即x中每个元素的元组列表,y中的每个元素......做我想做的事情的正确方法是什么?谢谢...

EDIT: The other two duplicates mentioned before the edit is my fault, indented it in another for-loop by mistake...

编辑:在编辑之前提到的另外两个重复是我的错误,错误地将它缩进到另一个for循环中...

3 个解决方案

#1

Use the builtin function zip():

使用内置函数zip():

In Python 3:

在Python 3中:

z = list(zip(x,y))

In Python 2:

在Python 2中:

z = zip(x,y)

#2

You're looking for the zip builtin function. From the docs:

您正在寻找zip内置功能。来自文档:

>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> zipped
[(1, 4), (2, 5), (3, 6)]

#3

You're after the zip function.

你是在拉链功能之后。

Taken directly from the question: How to merge lists into a list of tuples in Python?

直接来自问题:如何将列表合并到Python中的元组列表中?

>>> list_a = [1, 2, 3, 4]
>>> list_b = [5, 6, 7, 8]
>>> zip(list_a,list_b)
[(1, 5), (2, 6), (3, 7), (4, 8)]

#1