I am trying to make a POST request to the following page:http://search.cpsa.ca/PhysicianSearch
我正在尝试向以下页面发出POST请求:http://search.cpsa.ca/PhysicianSearch
In order to simulate clicking the 'Search' button without filling out any of the form, which adds data to the page. I got the POST header information by clicking on the button while looking at the network tab in chrome developer tools. The reason I'm posting this instead of just copying solutions from the other similar problems is that I believe I may have not gotten the correct header information. Is it properly formatted and did I grab the right information? I've never made a POST request before.
为了模拟单击“搜索”按钮而不填写任何表单,这会向页面添加数据。通过在查看chrome developer工具中的网络选项卡时单击按钮,我获得了POST标头信息。我发布这个而不是仅仅从其他类似问题复制解决方案的原因是我相信我可能没有得到正确的标题信息。格式是否正确,我是否抓住了正确的信息?我之前从未发过过POST请求。
This is what I've managed to piece together:
这就是我设法拼凑的东西:
import urllib.parse
import urllib.request
data = urllib.parse.urlencode({'Host': 'search.cpsa.ca', 'Connection': 'keep-alive', 'Content-Length': 23796,
'Origin': 'http://search.cpsa.ca', 'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
'Cahce-Control': 'no-cache', 'X-Requested-With': 'XMLHttpRequest',
'X-MicrosoftAjax': 'Delta=true', 'Accept': '*/*',
'Referer': 'http://search.cpsa.ca/PhysicianSearch',
'Accept-Encoding': 'gzip, deflate',
'Accept-Language': 'en-GB,en-US;q=0.8,en;q=0.6',
'Cookie': 'ASP.NET_SessionId=kcwsgio3dchqjmyjtwue402c; _ga=GA1.2.412607756.1459536682; _gat=1'})
url = "http://www.musi-cal.com/cgi-bin/query?%s"
data = data.encode('ascii')
with urllib.request.urlopen("http://search.cpsa.ca/PhysicianSearch", data) as f:
print(f.read().decode('utf-8'))
This solution outputs the page's HTML, but not with any of the data I wanted to retrieve from the POST request.
此解决方案输出页面的HTML,但不包含我想要从POST请求中检索的任何数据。
2 个解决方案
#1
29
This is how you do it.
这就是你如何做到的。
from urllib import request, parse
data = parse.urlencode(<your data dict>).encode()
req = request.Request(<your url>, data=data) # this will make the method "POST"
resp = request.urlopen(req)
#2
2
Thank you C Panda. You really made it easy for me to learn this module.
谢谢C熊猫。你真的让我很容易学习这个模块。
I released the dictionary that we pass does not encode for me. I had to do a minor change -
我发布了我们传递的字典,不为我编码。我不得不做一个小改动 -
from urllib import request, parse
import json
# Data dict
data = { 'test1': 10, 'test2': 20 }
# Dict to Json
# Difference is { "test":10, "test2":20 }
data = json.dumps(data)
# Convert to String
data = str(data)
# Convert string to byte
data = data.encode('utf-8')
# Post Method is invoked if data != None
req = request.Request(<your url>, data=data)
# Response
resp = request.urlopen(req)
#1
29
This is how you do it.
这就是你如何做到的。
from urllib import request, parse
data = parse.urlencode(<your data dict>).encode()
req = request.Request(<your url>, data=data) # this will make the method "POST"
resp = request.urlopen(req)
#2
2
Thank you C Panda. You really made it easy for me to learn this module.
谢谢C熊猫。你真的让我很容易学习这个模块。
I released the dictionary that we pass does not encode for me. I had to do a minor change -
我发布了我们传递的字典,不为我编码。我不得不做一个小改动 -
from urllib import request, parse
import json
# Data dict
data = { 'test1': 10, 'test2': 20 }
# Dict to Json
# Difference is { "test":10, "test2":20 }
data = json.dumps(data)
# Convert to String
data = str(data)
# Convert string to byte
data = data.encode('utf-8')
# Post Method is invoked if data != None
req = request.Request(<your url>, data=data)
# Response
resp = request.urlopen(req)