Django URLS，如何将root映射到app？

I am pretty new to django but experienced in Python and java web programming with different frameworks. I have made myself a nice little django app, but I cant seem to make it match www.mysite.com as opposed to www.mysite.com/myapp.

我是django的新手，但在使用不同框架的Python和java web编程方面经验丰富。我已经为自己做了一个不错的小django应用程序，但我似乎无法使它与www.mysite.com相匹配而不是www.mysite.com/myapp。

I have defined urls and views in my urls.conf which is currently not decoupled from the app (don't mind that).

我在urls.conf中定义了网址和视图，这些网址目前没有与应用程序分离（不介意）。

urlpatterns = patterns('myapp.views',
  (r'^myapp/$', 'index'),
  (r'^myapp/(?P<some_id>\d+)/global_stats/$', 'global_stats'),
  (r'^myapp/(?P<some_id>\d+)/player/(?P<player_id>\d+)/$', 'player_stats'),
)

All this works like a charm. If someone goes to www.mysite.com/myapp they will hit my index view which causes a http redirect to my "correct" default url.

所有这一切都像一个魅力。如果有人访问www.mysite.com/myapp，他们将点击我的索引视图，这会导致http重定向到我的“正确”默认网址。

So, how can I add a pattern that will do the same as (r'^myapp/$', 'index') but without the /myapp--that is, www.mysite.com should suffice?

那么，我如何添加一个与（r'^ myapp / $'，'index'）相同的模式但没有/ myapp - 也就是说，www.mysite.com就足够了？

I would think this would be very basic stuff... I tried adding a line like:

我认为这将是非常基本的东西......我尝试添加如下行：

(r'^$', 'index'),

however this throws me in a loop...

然而这让我陷入了困境......

Hope you django gurus out there can clarify this for me!

希望你在那里的django大师可以为我澄清这个！

5 个解决方案

#1

This sounds strange.

这听起来很奇怪。

Your latest attempt should work, but what I normally do - put

你的最新尝试应该有效，但我通常做的是 - 放

urlpatterns = patterns('',
    (r'^$', lambda r: HttpResponseRedirect('myapp/')),
    ...
)

This scales better when you start adding new apps.

当您开始添加新应用时，这会更好地扩展。

#2

I know that this question was asked 2 years ago, but I've faced the same problem and found a solution:

我知道这个问题是2年前提出的，但我遇到了同样的问题并找到了解决方案：

In the project urls.py:

在项目urls.py中：

urlpatterns = patterns('',
    url(r'^', include('my_app.urls')), #NOTE: without $
)

In my_app.urls.py:

在my_app.urls.py中：

urlpatterns = patterns('',
    url(r'^$', 'my_app.views.home', name='home'),
    url(r'^v1/$', 'my_app.views.v1', name='name_1'),
    url(r'^v2/$', 'my_app.views.v2', name='name_2'),
    url(r'^v3/$', 'my_app.views.v3', name='name_3'),
)

#3

As I didn't see any answer for django 2.0 I thought I'll provide one. you have to use '' as the root url. Here is an example from django 2.0 docs

由于我没有看到django 2.0的任何答案，我以为我会提供一个。你必须使用''作为根网址。这是django 2.0 docs的一个例子

urlpatterns = [
    path('', main_views.homepage),
    path('help/', include('apps.help.urls')),
    path('credit/', include(extra_patterns)),
]

#4

Just put an empty raw regular expression: r''

只需放一个空的原始正则表达式：r''

I tested here and it worked perfectly.

我在这里测试过它完美无缺。

urlpatterns = patterns('',
    url(r'', include('homepage.urls')),
    url(r'^homepage/', include('homepage.urls')),
    url(r'^admin/', include(admin.site.urls)),
)

Hope it help!

希望它有所帮助！

#5

I know the answer is late, but i had my fair share of hunting recently. This is what i tried with CBV.. in Project urls.py

我知道答案已经很晚了，但最近我有相当多的狩猎。这是我在项目urls.py中尝试使用CBV ..

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^$', include('app_name.urls', namespace='app_name')),
]

PS: It is always recommended to use namespace. Gives a good advantage later on.

PS：始终建议使用命名空间。以后会给你一个很好的优势。

In App urls.py

在App urls.py中

urlpatterns = [
    url(r'^$', views.IndexPageView.as_view(), name='index'),
]

#1