this was my url.py
这是我的url.py
urlpatterns = patterns('',
url(r'/newm/$', views.CreateManView.as_view(), name='create_man'),
I've changed it to:
我已将其更改为:
url(r'http://y.y.y.y/newm/$', views.CreateManView.as_view(), name='create_man'),
but result in a call to:
但导致致电:
http://x.x.x.x/http://y.y.y.y/newm/
HTTP://x.x.x.x/http://y.y.y.y/newm/
how can I change all url that refer to create_man so they will get to
如何更改引用create_man的所有url,以便他们可以访问
HTTP://y.y.y.y/newm/
?
?
1 个解决方案
#1
1
Check out django-hosts, it does exactly that.
看看django-hosts,就是这样。
As for having it as a feature in Django, a core dev commented on this question:
至于将它作为Django中的一个功能,核心开发者就这个问题发表了评论:
This has been solved by external apps and I'm happy with that solution
这已经被外部应用程序解决了,我很满意这个解决方案
#1
1
Check out django-hosts, it does exactly that.
看看django-hosts,就是这样。
As for having it as a feature in Django, a core dev commented on this question:
至于将它作为Django中的一个功能,核心开发者就这个问题发表了评论:
This has been solved by external apps and I'm happy with that solution
这已经被外部应用程序解决了,我很满意这个解决方案