Django URL模板匹配（除模式外的所有内容）

I need a django regex that will actually work for the url router to do the following:

我需要一个django正则表达式,它实际上适用于url路由器执行以下操作:

Match everything that does not contain "/api" in the route.

匹配路线中不包含“/ api”的所有内容。

The following does not work because django can't reverse (?!

以下不起作用,因为django不能反转(?!

r'^(?!api)

3 个解决方案

#1

The usual way to go about this would be to order the route declarations so that the catch-all route is shadowed by the /api route, i.e.:

通常的方法是订购路由声明,以便全部路由被/ api路由遮蔽,即:

urlpatterns = patterns('', 
    url(r'^api/', include('api.urls')),
    url(r'^other/', 'views.other', name='other'),
    url(r'^.*$', 'views.catchall', name='catch-all'), 
)

Alternatively, if for some reason you really need to skip some routes but cannot do it with the set of regexes supported by Django, you could define a custom pattern matcher class:

或者,如果由于某种原因你真的需要跳过一些路由但不能用Django支持的一组正则表达式来做,你可以定义一个自定义模式匹配器类:

from django.core.urlresolvers import RegexURLPattern 

class NoAPIPattern(RegexURLPattern):
    def resolve(self, path):
        if not path.startswith('api'):
            return super(NoAPIPattern, self).resolve(path)

urlpatterns = patterns('',
    url(r'^other/', 'views.other', name='other'),
    NoAPIPattern(r'^.*$', 'views.catchall', name='catch-all'),
)

#2

Use a negative look behind like so:

像这样使用负面外观:

r'^(?!/api).*$'

This link explains how to do that:

此链接说明了如何执行此操作:

http://www.codinghorror.com/blog/2005/10/excluding-matches-with-regular-expressions.html

#3

I had this problem integrating django with react router, I check this link to fix it.

我有这个问题集成django与反应路由器,我检查此链接来修复它。

decoupled frontend and backend with Django, webpack, reactjs, react-router

与Django,webpack,reactjs,react-router解耦前端和后端

#1