^[A-Za-z](\ W | \ W)*正则表达式?

The regular expression ^[A-Za-z](\W|\w)* matches when the user gives the first letter as white space, and the first letter should not be a digit and remaining letters may be alpha numerical. When the user gives a white space as the first character it should automatically be trimmed. How?

正则表达式^[A-Za-z](\ W | \ W)*匹配当用户给第一个字母为空白,不应该第一个字母一个数字和剩下的字母可能是α数值。当用户将空格作为第一个字符时，它应该自动被修改。如何?

2 个解决方案

#1

^\s*([A-Za-z]\w*)

Should do it. Just get group 1.

应该这样做。组1。

I'm not sure the language you are using, I'm going to assume C#, so here is a C# sample:

我不确定你用的是哪种语言，我假设是c#，这里有一个c#示例:

string testString = "       myMatch123 not in the match";

Regex regexObj = new Regex("^\\s*([A-Za-z]\\w*)", 
                        RegexOptions.IgnoreCase | RegexOptions.Multiline);
string result = regexObj.Match(testString).Groups[1].Value;

Console.WriteLine("-" + result + "-");

This will print

这将打印

-myMatch123-

to the console window.

到控制台窗口。

#2

Is it possible to Trim() your input before giving it to your regex?

是否可以在将输入内容提供给regex之前对其进行修剪?

If you're looking for alpha-numerical, starting with non-numeric, you probably want:

如果您正在寻找alpha- numbers，从非numeric开始，您可能需要:

\s*([A-Za-z][A-Za-z0-9]+)

If you allow one-character user names, change that plus to a star.

如果你只允许一个字符的用户名，那就把这个加号改成星号。

#1

^\s*([A-Za-z]\w*)