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- How to run shell script with live feedback from PHP? 2 answers
如何使用PHP的实时反馈运行shell脚本? 2个答案
i am running one linux command with shell_exec() in my php script.
我在我的PHP脚本中运行一个带有shell_exec()的linux命令。
$output = shell_exec('/usr/bin/linux-command ');
After execution of the command i am getting the value into a variable. That's okay.
But, here my linux command will give the output continuously in terminal.
It will come like this..
执行命令后,我将值变为变量。没关系。但是,这里我的linux命令将在终端中持续提供输出。会是这样的......
$linux-command
123 456 789
789 456 123
123 456 789 .. //and so on..(by pressing 'Ctrl+c' only we can stop this.
For every 5 seconds it will display one line. how to retrieve the line for every 5 sec.
My Page is in loading ........ Because, it is waiting for the $output.
Is there any way to solve my problem ??
Any idea is appreciated. Thank you in advance
每5秒钟它会显示一行。如何每5秒检索一次。我的页面正在加载........因为,它正在等待$输出。有什么方法可以解决我的问题吗?任何想法都表示赞赏。先谢谢你
2 个解决方案
#1
1
Try the passthru function. The output is displayed directly. You can test it with this small script:
尝试passthru功能。输出直接显示。你可以用这个小脚本来测试它:
<?php
passthru('tail -f /var/log/apache2/access.log');
?>
#2
#1
1
Try the passthru function. The output is displayed directly. You can test it with this small script:
尝试passthru功能。输出直接显示。你可以用这个小脚本来测试它:
<?php
passthru('tail -f /var/log/apache2/access.log');
?>