In a Linux terminal, how to delete all files from a folder except one or two?
在Linux终端中,如何从一个或两个文件夹中删除所有文件?
For example.
例如。
I have 100 image files in a directory and one .txt
file. I want to delete all files except that .txt
file.
我在目录中有100个图像文件和一个.txt文件。我想删除除.txt文件以外的所有文件。
5 个解决方案
#1
31
From within the directory, list the files, filter out all not containing 'file-to-keep', and remove all files left on the list.
在目录中,列出文件,过滤掉所有不包含'file-to-keep'的文件,并删除列表中剩余的所有文件。
ls | grep -v 'file-to-keep' | xargs rm
To avoid issues with spaces in filenames (remember to never use spaces in filenames), use find
and -0
option.
要避免文件名中的空格问题(请记住永远不要在文件名中使用空格),请使用find和-0选项。
find 'path' -maxdepth 1 -not -name 'file-to-keep' -print0 | xargs -0 rm
Or mixing both, use grep
option -z
to manage the -print0
names from find
或者混合两者,使用grep选项-z来管理来自find的-print0名称
#2
8
In general, using an inverted pattern search with grep should do the job. As you didn't define any pattern, I'd just give you a general code example:
通常,使用grep的反向模式搜索应该可以完成这项工作。由于您没有定义任何模式,我只是给您一个通用代码示例:
ls -1 | grep -v 'name_of_file_to_keep.txt' | xargs rm -f
The ls -1
lists one file per line, so that grep can search line by line. grep -v
is the inverted flag. So any pattern matched will NOT be deleted.
ls -1每行列出一个文件,以便grep可以逐行搜索。 grep -v是倒置标志。因此,任何匹配的模式都不会被删除。
For multiple files, you may use egrep:
对于多个文件,您可以使用egrep:
ls -1 | grep -E -v 'not_file1.txt|not_file2.txt' | xargs rm -f
Update after question was updated: I assume you are willing to delete all files except files in the current folder that do not end with .txt
. So this should work too:
问题更新后更新:我假设您愿意删除除当前文件夹中不以.txt结尾的文件之外的所有文件。所以这也应该有效:
find . -maxdepth 1 -type f -not -name "*.txt" -exec rm -f {} \;
#3
4
find supports a -delete
option so you do not need to -exec
. You can also pass multiple sets of -not -name somefile -not -name otherfile
find支持-delete选项,因此您不需要-exec。您还可以传递多组-not -name somefile -not -name otherfile
user@host$ ls
1.txt 2.txt 3.txt 4.txt 5.txt 6.txt 7.txt 8.txt josh.pdf keepme
user@host$ find . -maxdepth 1 -type f -not -name keepme -not -name 8.txt -delete
user@host$ ls
8.txt keepme
#4
3
Use the not
modifier to remove file(s)
or pattern(s)
you don't want to delete, you can modify the 1
passed to -maxdepth
to specify how many sub directories deep you want to delete files from
使用not修饰符删除您不想删除的文件或模式,您可以修改传递给-maxdepth的1,以指定要从中删除文件的深度子目录数
find . -maxdepth 1 -not -name "*.txt" -exec rm -f {} \;
You can also do:
你也可以这样做:
find -maxdepth 1 \! -name "*.txt" -exec rm -f {} \;
#5
2
In bash, you can use:
在bash中,您可以使用:
$ shopt -s extglob # Enable extended pattern matching features
$ rm !(*.txt) # Delete all files except .txt files
#1
31
From within the directory, list the files, filter out all not containing 'file-to-keep', and remove all files left on the list.
在目录中,列出文件,过滤掉所有不包含'file-to-keep'的文件,并删除列表中剩余的所有文件。
ls | grep -v 'file-to-keep' | xargs rm
To avoid issues with spaces in filenames (remember to never use spaces in filenames), use find
and -0
option.
要避免文件名中的空格问题(请记住永远不要在文件名中使用空格),请使用find和-0选项。
find 'path' -maxdepth 1 -not -name 'file-to-keep' -print0 | xargs -0 rm
Or mixing both, use grep
option -z
to manage the -print0
names from find
或者混合两者,使用grep选项-z来管理来自find的-print0名称
#2
8
In general, using an inverted pattern search with grep should do the job. As you didn't define any pattern, I'd just give you a general code example:
通常,使用grep的反向模式搜索应该可以完成这项工作。由于您没有定义任何模式,我只是给您一个通用代码示例:
ls -1 | grep -v 'name_of_file_to_keep.txt' | xargs rm -f
The ls -1
lists one file per line, so that grep can search line by line. grep -v
is the inverted flag. So any pattern matched will NOT be deleted.
ls -1每行列出一个文件,以便grep可以逐行搜索。 grep -v是倒置标志。因此,任何匹配的模式都不会被删除。
For multiple files, you may use egrep:
对于多个文件,您可以使用egrep:
ls -1 | grep -E -v 'not_file1.txt|not_file2.txt' | xargs rm -f
Update after question was updated: I assume you are willing to delete all files except files in the current folder that do not end with .txt
. So this should work too:
问题更新后更新:我假设您愿意删除除当前文件夹中不以.txt结尾的文件之外的所有文件。所以这也应该有效:
find . -maxdepth 1 -type f -not -name "*.txt" -exec rm -f {} \;
#3
4
find supports a -delete
option so you do not need to -exec
. You can also pass multiple sets of -not -name somefile -not -name otherfile
find支持-delete选项,因此您不需要-exec。您还可以传递多组-not -name somefile -not -name otherfile
user@host$ ls
1.txt 2.txt 3.txt 4.txt 5.txt 6.txt 7.txt 8.txt josh.pdf keepme
user@host$ find . -maxdepth 1 -type f -not -name keepme -not -name 8.txt -delete
user@host$ ls
8.txt keepme
#4
3
Use the not
modifier to remove file(s)
or pattern(s)
you don't want to delete, you can modify the 1
passed to -maxdepth
to specify how many sub directories deep you want to delete files from
使用not修饰符删除您不想删除的文件或模式,您可以修改传递给-maxdepth的1,以指定要从中删除文件的深度子目录数
find . -maxdepth 1 -not -name "*.txt" -exec rm -f {} \;
You can also do:
你也可以这样做:
find -maxdepth 1 \! -name "*.txt" -exec rm -f {} \;
#5
2
In bash, you can use:
在bash中,您可以使用:
$ shopt -s extglob # Enable extended pattern matching features
$ rm !(*.txt) # Delete all files except .txt files