用报头发送HTTP GET请求

时间:2021-03-12 16:54:41

From my Android app I want to request a URL with GET parameters and read the response. In the request I must add a x-zip header.

我想从我的Android应用程序中请求一个带有GET参数的URL并读取响应。在请求中,我必须添加一个x-zip头。

The URL is something like

URL是这样的

http://example.com/getmethod.aspx?id=111&method=Test

Can some one provide me code for that?

有人能给我提供代码吗?

Two things are important: that it is a GET request and contains the x-zip header .

有两件事很重要:它是GET请求,包含x-zip报头。

EDIT:

编辑:

try {
    HttpClient client = new DefaultHttpClient();  
    String getURL = "http://example.com/getmethod.aspx?id=111&method=Test";
    HttpGet get = new HttpGet(getURL);
    get.setHeader("Content-Type", "application/x-zip");
    HttpResponse responseGet = client.execute(get);  
    HttpEntity resEntityGet = responseGet.getEntity();  
    if (resEntityGet != null) {  
        //do something with the response
        Log.i("GET ",EntityUtils.toString(resEntityGet));
    }
} catch (Exception e) {
    e.printStackTrace();
}

I try with this code but I get code with .net error: Object reference not set to an instance of an object... I think but I'm not sure this if for x-zip header, is header in my code ok?

我尝试使用这段代码,但是我得到的代码是。net error: Object reference而不是对象的实例…我想,但是我不确定如果x-zip头,头在我的代码中,好吗?

2 个解决方案

#1


11  

Here's a code excerpt we're using in our app to set request headers. You'll note we set the CONTENT_TYPE header only on a POST or PUT, but the general method of adding headers (via a request interceptor) is used for GET as well.

这是我们在应用程序中用来设置请求头的代码摘录。您会注意到,我们只在POST或PUT上设置CONTENT_TYPE头,但是添加header(通过请求拦截器)的一般方法也用于GET。

/**
 * HTTP request types
 */
public static final int POST_TYPE   = 1;
public static final int GET_TYPE    = 2;
public static final int PUT_TYPE    = 3;
public static final int DELETE_TYPE = 4;

/**
 * HTTP request header constants
 */
public static final String CONTENT_TYPE         = "Content-Type";
public static final String ACCEPT_ENCODING      = "Accept-Encoding";
public static final String CONTENT_ENCODING     = "Content-Encoding";
public static final String ENCODING_GZIP        = "gzip";
public static final String MIME_FORM_ENCODED    = "application/x-www-form-urlencoded";
public static final String MIME_TEXT_PLAIN      = "text/plain";

private InputStream performRequest(final String contentType, final String url, final String user, final String pass,
    final Map<String, String> headers, final Map<String, String> params, final int requestType) 
            throws IOException {

    DefaultHttpClient client = HTTPClientFactory.newClient();

    client.getParams().setParameter(HttpProtocolParams.USER_AGENT, mUserAgent);

    // add user and pass to client credentials if present
    if ((user != null) && (pass != null)) {
        client.getCredentialsProvider().setCredentials(AuthScope.ANY, new UsernamePasswordCredentials(user, pass));
    }

    // process headers using request interceptor
    final Map<String, String> sendHeaders = new HashMap<String, String>();
    if ((headers != null) && (headers.size() > 0)) {
        sendHeaders.putAll(headers);
    }
    if (requestType == HTTPRequestHelper.POST_TYPE || requestType == HTTPRequestHelper.PUT_TYPE ) {
        sendHeaders.put(HTTPRequestHelper.CONTENT_TYPE, contentType);
    }
    // request gzip encoding for response
    sendHeaders.put(HTTPRequestHelper.ACCEPT_ENCODING, HTTPRequestHelper.ENCODING_GZIP);

    if (sendHeaders.size() > 0) {
        client.addRequestInterceptor(new HttpRequestInterceptor() {

            public void process(final HttpRequest request, final HttpContext context) throws HttpException,
                IOException {
                for (String key : sendHeaders.keySet()) {
                    if (!request.containsHeader(key)) {
                        request.addHeader(key, sendHeaders.get(key));
                    }
                }
            }
        });
    }

    //.... code omitted ....//

}

#2


6  

You do it exactly as you showed with this line:

你做的和你展示的一样:

get.setHeader("Content-Type", "application/x-zip");

So your header is fine and the problem is some other input to the web service. You'll want to debug that on the server side.

你的头很好,问题是web服务的其他输入。您将希望在服务器端进行调试。

#1


11  

Here's a code excerpt we're using in our app to set request headers. You'll note we set the CONTENT_TYPE header only on a POST or PUT, but the general method of adding headers (via a request interceptor) is used for GET as well.

这是我们在应用程序中用来设置请求头的代码摘录。您会注意到,我们只在POST或PUT上设置CONTENT_TYPE头,但是添加header(通过请求拦截器)的一般方法也用于GET。

/**
 * HTTP request types
 */
public static final int POST_TYPE   = 1;
public static final int GET_TYPE    = 2;
public static final int PUT_TYPE    = 3;
public static final int DELETE_TYPE = 4;

/**
 * HTTP request header constants
 */
public static final String CONTENT_TYPE         = "Content-Type";
public static final String ACCEPT_ENCODING      = "Accept-Encoding";
public static final String CONTENT_ENCODING     = "Content-Encoding";
public static final String ENCODING_GZIP        = "gzip";
public static final String MIME_FORM_ENCODED    = "application/x-www-form-urlencoded";
public static final String MIME_TEXT_PLAIN      = "text/plain";

private InputStream performRequest(final String contentType, final String url, final String user, final String pass,
    final Map<String, String> headers, final Map<String, String> params, final int requestType) 
            throws IOException {

    DefaultHttpClient client = HTTPClientFactory.newClient();

    client.getParams().setParameter(HttpProtocolParams.USER_AGENT, mUserAgent);

    // add user and pass to client credentials if present
    if ((user != null) && (pass != null)) {
        client.getCredentialsProvider().setCredentials(AuthScope.ANY, new UsernamePasswordCredentials(user, pass));
    }

    // process headers using request interceptor
    final Map<String, String> sendHeaders = new HashMap<String, String>();
    if ((headers != null) && (headers.size() > 0)) {
        sendHeaders.putAll(headers);
    }
    if (requestType == HTTPRequestHelper.POST_TYPE || requestType == HTTPRequestHelper.PUT_TYPE ) {
        sendHeaders.put(HTTPRequestHelper.CONTENT_TYPE, contentType);
    }
    // request gzip encoding for response
    sendHeaders.put(HTTPRequestHelper.ACCEPT_ENCODING, HTTPRequestHelper.ENCODING_GZIP);

    if (sendHeaders.size() > 0) {
        client.addRequestInterceptor(new HttpRequestInterceptor() {

            public void process(final HttpRequest request, final HttpContext context) throws HttpException,
                IOException {
                for (String key : sendHeaders.keySet()) {
                    if (!request.containsHeader(key)) {
                        request.addHeader(key, sendHeaders.get(key));
                    }
                }
            }
        });
    }

    //.... code omitted ....//

}

#2


6  

You do it exactly as you showed with this line:

你做的和你展示的一样:

get.setHeader("Content-Type", "application/x-zip");

So your header is fine and the problem is some other input to the web service. You'll want to debug that on the server side.

你的头很好,问题是web服务的其他输入。您将希望在服务器端进行调试。