用较低的第一个char替换方法名称

need some help. Wanna replace all method names in code with rule:

需要一些帮助。想用代码替换代码中的所有方法名称:

MethodName -> methodName (need for cpp translation).

Unfortunatelly, I need to escape in my Regex all cases that started with new.

不幸的是,我需要在我的正则表达式中逃避所有以新的开头的情况。

My regex:

 `[>\\.\\s]+[A-Z]+[a-zA-Z0-9_]*\\({1}`

It matches to

它符合

`>MethodName(`, `.MethodName(` ` MethodName(`

but also in last case can be new ClassName.

但在最后一种情况下也可以是新的ClassName。

How to avoid this case?

如何避免这种情况?

2 个解决方案

#1

You can use this regex:

你可以使用这个正则表达式:

(?<!new)[>.\s]+[A-Z]+\w*\(

(?<!new) is a negative lookbehind, it will ensure that the method name is not preceded by the keyword new.

I also:

changed [a-zA-Z0-9_] to \w since it's equivalent;

将[a-zA-Z0-9_]更改为\ w,因为它是等效的;

remove the quantifier {1} which was redundant.

删除多余的量词{1}。

#2

Do you need to find with leading space? If not:

你需要找到领先的空间吗?如果不:

First character may by > or .

第一个字符可以>或。

Followed by capital letter

其次是大写字母

Follwed by zero or more letter,number or underline

由零个或多个字母,数字或下划线表示

Followed by (

其次是 (

[>|\.]([A-Z][a-zA-Z0-9_])*\(

#1