I just started with regex and sed, and I am having an issue with the following:
我刚开始使用regex和sed，我有以下问题:
echo "abc2def3ghi" | sed 's/^\(.*\)[0-9]\(.*\)$/"&" \1\2/i'
I am looking to remove the first digit (2 in this case, but can by any single digit), but I get the following as a result:
我想删除第一个数字(在这种情况下是2，但是可以删除任何一个数字)，但是我得到以下结果:
"abc2def3ghi" abc2defghi
How would I go about accomplishing this?
我该怎么做呢?
Thanks.
谢谢。
2 个解决方案
#1
2
Try this :
试试这个:
sed 's/[0-9]//1' file.txt
The number 1 in s///1 stands for Nth occurence
s///1中的数字1表示第n次发生
#2
1
sed has no reluctant/non-greedy quantifier, so you have to match zero or more non-digits specifically:
sed没有不情愿的/非贪婪的量词，因此您必须特别匹配零或更多非数字:
^\([^0-9]*\)[0-9]\(.*\)$
#1
2
Try this :
试试这个:
sed 's/[0-9]//1' file.txt
The number 1 in s///1 stands for Nth occurence
s///1中的数字1表示第n次发生
#2
1
sed has no reluctant/non-greedy quantifier, so you have to match zero or more non-digits specifically:
sed没有不情愿的/非贪婪的量词，因此您必须特别匹配零或更多非数字:
^\([^0-9]*\)[0-9]\(.*\)$