获取错误HTTP状态405 - 此方法不支持HTTP方法GET但不使用`get`？

I'm a beginner and making a small registration program with database But i'm trying to run this but it's giving me some errors pls help:

我是初学者并使用数据库制作一个小型注册程序但是我正在尝试运行这个但是它给了我一些错误请帮忙：

HTTP Status 405 - HTTP method GET is not supported by this URL

type Status report

message HTTP method GET is not supported by this URL

description The specified HTTP method is not allowed for the requested resource.
Apache Tomcat/8.0.5

And here is my register.html codes:

这是我的register.html代码：

<html>
<head lang="en">
    <meta charset="UTF-8">
    <title></title>
</head>
<body>
<form action="Register" method="post">
    Name: <input type="text" name="name">
    Email: <input type="text" name="email">
    Password: <input type="password" name="password">
    Country:

    <select name="userCountry">
        <option>India</option>
        <option>Pakistan</option>
        <option>Other</option>
    </select><br><br>

    <input type="submit" value="register">
</form>
</body>
</html>

Here is my Register.java codes:

这是我的Register.java代码：

import java.sql.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;

public class Register extends HttpServlet{
    public void doPost(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException{
        response.setContentType("text/html");
        PrintWriter out=response.getWriter();

        String n=request.getParameter("name");
        String p=request.getParameter("password");
        String e=request.getParameter("email");
        String c=request.getParameter("userCountry");

        try{
            Connection con=DriverManager.getConnection(
                    "jdbc:mysql://localhost:8888", "root", "1234"
            );

            PreparedStatement ps=con.prepareStatement("insert into REGISTERUSER values(?, ?, ?, ?)");

            ps.setString(1,n);
            ps.setString(2,p);
            ps.setString(3,e);
            ps.setString(4,c);

            int i=ps.executeUpdate();
            if(i>0){
                out.print("Registered successfully..");
            }

        }catch(Exception d){d.printStackTrace();}
        out.close();
    }
}

And here is my Web.xml:

这是我的Web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

    <servlet>
        <servlet-name>Register</servlet-name>
        <servlet-class>Register</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>Register</servlet-name>
        <url-pattern>/register.html</url-pattern>
    </servlet-mapping>
    <welcome-file-list>
        <welcome-file>register.html</welcome-file>
    </welcome-file-list>
</web-app>

Help would be appreciated!!

帮助将不胜感激!!

3 个解决方案

#1

The problem is that you mapped your servlet to /register.html and it expects POST method, because you implemented only doPost() method. So when you open register.html page, it will not open html page with the form but servlet that handles the form data.

问题是您将servlet映射到/register.html并且它期望POST方法，因为您只实现了doPost（）方法。所以当你打开register.html页面时，它不会打开带有表单的html页面，而是打开处理表单数据的servlet。

Alternatively when you submit POST form to non-existing URL, web container will display 405 error (method not allowed) instead of 404 (not found).

或者，当您将POST表单提交到不存在的URL时，Web容器将显示405错误（不允许方法）而不是404（未找到）。

To fix:

修理：

<servlet-mapping>
    <servlet-name>Register</servlet-name>
    <url-pattern>/Register</url-pattern>
</servlet-mapping>

#2

I think your issue may be in the url pattern. Changing

我认为您的问题可能是网址模式。更改

<servlet-mapping>
    <servlet-name>Register</servlet-name>
    <url-pattern>/Register</url-pattern>
</servlet-mapping>

and

和

<form action="/Register" method="post">

may fix your problem

可以解决你的问题

#3

Override service method like this:

像这样覆盖服务方法：

protected void service(HttpServletRequest request, HttpServletResponse   response) throws ServletException, IOException {
        doPost(request, response);
}

And Voila!

还有瞧！

#1