PHP：如何在字符串中的某些关键字之前删除所有内容？

I have these type of results from a loop function,

我有循环函数的这些类型的结果,

C:/wamp/www/xxx/core/page/
C:/wamp/www/xxx/local/page/

But how can I trim off anything before core or local, so I get these only,

但是如何在核心或本地之前修剪掉任何东西,所以我只能得到这些,

core/page/
local/page/

I use strstr, but I think it search for a fixed keyword only, I have two, many more keywords to match,

我使用strstr,但我认为它只搜索一个固定的关键字,我有两个,更多的关键字匹配,

$string = 'C:/wamp/www/xxx/local/page/';
$output = strstr($string, '(local|core)');
var_dump($output);

I tried with preg_replace,

我试过preg_replace,

var_dump(preg_replace('#/(core|local)/.*#si', '/', $string));

it gives me the front part - C:/wamp/www/xxx/

它给了我前面部分 - C:/ wamp / www / xxx /

6 个解决方案

#1

You can use preg_replace like this:

您可以像这样使用preg_replace:

$output = preg_replace('~^.*?((?:core|local).*$)~i', "$1", $string);

$output = preg_replace('~^.*?(?=core|local)~i', '', $string);

If you want to match strictly up to the folder core or local, you can use this:

如果要严格匹配文件夹核心或本地,可以使用:

$output = preg_replace('~^.*?/(?=(?:core|local)/)~i', '', $string);

Viper-7 demo

To your question:

对你的问题:

var_dump(preg_replace('#/(core|local)/.*#si', '/', $string));

This will match /(core|local)/.* and replace it by /, which is not really what you're looking for, because you actually have to match what is before this. My first regex here is an example of that: it will match everything before (?:core|local) and then capture everything which comes afterwards into a capture group, which I'm referring to when using the backreference $1.

这将匹配/(core|local)/.*并用/替换它,这实际上不是你想要的,因为你实际上必须匹配之前的内容。我的第一个正则表达式就是这样一个例子:它将匹配之前的所有内容(?:core | local),然后捕获随后进入捕获组的所有内容,我在使用反向引用$ 1时将其引用。

And well, because of the votewar going here... I added the forward slashes in the match, and you will be using less memory if you don't use a capture group at all (but using a lookahead), hence how I came to the last regex.

好吧,因为投票战在这里...我在比赛中添加了正斜杠,如果你根本不使用捕获组(但是使用前瞻),你将使用更少的内存,因此我是如何来的到最后一个正则表达式。

#2

Your code will be like:

你的代码就像:

$sData   = 'C:/wamp/www/xxx/local/page/';
$sResult = preg_replace('/^(.*?)\/(core|local)\/(.*?)$/', '$2/$3', $sData);

#3

Use preg_match()

<?
    $dir = "C:/wamp/www/xxx/core/page/";
    preg_match("#^.*?/((?:local|core).*/)$#i",$dir,$match);
    echo $match[1];
?>

If the first bit of the string is always the same you can use
echo ltrim($dir, "C:/wamp/www/xxx/");

如果字符串的第一位始终相同,则可以使用echo ltrim($ dir,“C:/ wamp / www / xxx /”);

#4

$output = substr($string, strpos($string,'local/')+strpos($string,'core/'));

#5

You can do it in a different way using str_replace. Check below.

您可以使用str_replace以不同的方式执行此操作。检查下面。

$string = 'C:/wamp/www/xxx/local/page/';
$output = str_replace('C:/wamp/www/xxx/' , '' , $string);
var_dump($output);

It will simply trim off the left side string.

它只会修剪左侧的弦。

#6

-4

preg_replace('/.*(core|local)/', "$1", $string);

#1